Y=3x-9
So when x is 16
Y=3(16)-9
Y=48-9
Y=39
The answer is c
Answer: The initial volume is 593.76mL
Step-by-step explanation:
As you do not say anithing about the pressure, i guess that the pressure remains constant.
If the gas is an ideal gas, we have:
P*V = n*R*T
where P is pressure, n is number of moles and R is a constant.
Now, initially we have:
P*Vi = n*R*315°C
finally we have:
P*825mL = n*R*452°C
Now we can take the quiotient of those two equations and get:
(P*Vi)/(P*852mL) = (n*R*315°C)/( n*R*452°C)
Now we have:
Vi/852mL = 315/452
Vi = (315/452)*852mL = 593.76mL
So when we expand the gas at constant pressure, we increase the temperature.
Firstly, I noticed that there are fractions, decimals, and percents. I will change everything to percents, so it’s more easy for me to compare each of them.
List 1. 140%, 25%, 14%. This is from greatest to least, not least to greatest.
List 2. 25%, 14%, 14%. This is not from least to greatest, either.
List 3. 14%, 25%, 140%. This is from least to greatest.
List 4. 140%, 14%, 25%. This is not from least to greatest.
List 3 is from least to greatest. I got this answer by converting all of the fractions and decimals to percentages.
Answer:
Exponential transformation.
Step-by-step explanation:
y = log_3 (x + 3) - 2
To transform this into exponential, we have:
Adding 2 to both sides
y + 2 = log_3 (x + 3)
3^(y + 2) = x + 3
x = 3^(y + 2) - 3
Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
