Answer:
The dimensions of the rectangle are 22cm of length and 15cm of width
Step-by-step explanation:
To solve this we first have to know the formula to calculate the area of a rectangle
a = area = 330 cm²
L = length =
w = width = L - 7cm
a = l * w
we replace with the known values
330 cm² = L * (l - 7cm)
330 cm² = L² - 7Lcm
0 = L² - 7Lcm - 330 cm²
when we have an equation like this we can use bhaskara
a = 1
b = -7Lcm
c = -330cm²
ax² + bx + c = 0
x = -b(±)√(b² - 4ac)/2a
we replace with the known values
L = -(-7cm)(±)√(7² - 4(1)(-330cm²)) / 2(1)
L = 7cm(±)√(49 + 1320cm²)) / 2
L = 7cm(±)√(1369cm²)) / 2
L1 = (7cm + 37cm) / 2
L1 = 44cm / 2 = 22cm
L2 = (7cm - 37cm) / 2
L2 = -30cm / 2 = -15cm
The positive represents the unknown with which we work (L) and the negative with which we do not work (W)
The dimensions of the rectangle are 22cm of length and 15cm of width
I am not sure if it is the best but heres one way to do it
Straight line = supplementary
Combine angles = 180 degrees
5x + 13x = 180
Solution: C
Answer:
The correct option is
x equals the square root of w times the sum of w plus z end quantity
Step-by-step explanation:
The parameters given are
ABC = Right triangle, with ∠B = 90° and CA = Hypotenuse = CD + DA
∴ CA = w + z
BA = v
Hence;
x² = (w + z)² - v²
Where:
v² = z² + y²
∴ x² = (w + z)² - (z² + y²)
x² = w² + 2·w·z + z² - z² - y²
x² = w² + 2·w·z - y²
Where:
y² = x² - w²
We have;
x² = w² + 2·w·z - (x² - w²)
x² = w² + 2·w·z - x² + w²
Which gives;
2·x² = 2·w² + 2·w·z
Removing the common factors, we have;
x² = w² + w·z
The correct option is x equals the square root of w times the sum of w plus z end quantity.
257 is a whole number, interger, and a rational number.