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k0ka [10]
3 years ago
8

Which is the best first step when solving the following system of equations? y= 7x+3 y=9x

Mathematics
1 answer:
Liula [17]3 years ago
4 0
I am not sure if it is the best but heres one way to do it 

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What are the zeros of the function f(x)=x^2-2x-15?
valkas [14]
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
Read 2 more answers
HELP MEEEE!!!<br><br> which of these graphs do not represent constant rates of change ?
Ganezh [65]

Answer:

Hello! Your answer would be below!

Step-by-step explanation:

Graph B)

Hope I helped! Ask me anything if you have questions!

3 0
3 years ago
Help for question 1 and 2​
AnnyKZ [126]

Answer:

<em>(1). </em>5^{4}<em> × </em>13^{7}<em> ; (2). 3 - 5x</em>

Step-by-step explanation:

1). [( - 5 )³ · ( - 5 )] ( 13^{-2} · 13^{9} ) = (-5)^{3+1} × (13)^{-2+9} = (-5)^{4} × 13^{7} = 5^{4} × 13^{7}

2). - 25x² ÷ 5x + 15x ÷ 5x = <em>3 - 5x</em>

4 0
2 years ago
I need answers 1-4. i don’t understand how to figure out the answers
klasskru [66]

answersssssssssssssss to ?


8 0
3 years ago
suppose 5 men and 7 women are on a crowded elevator. at the next floor, four people get off the elevator. find the probability t
lubasha [3.4K]
The total number of arrangements for all of them to be women is:
C(7, 4) because the order does not matter; we'd still have the same arrangements.

Now, we can simplify this:
C(7, 4) = \frac{7!}{4!(7 - 4)!}
= \frac{5040}{4!3!}
= \frac{5040}{24 \cdot 6}
= \frac{5040}{144} = 35

Now, the total number of arrangements, without restriction, is simply: C(12, 4) because we don't care who we pick.

\text{P(4 women): } \frac{35}{495} = \frac{7}{99}
3 0
3 years ago
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