A point is chosen at random in the circle. What percent of the time will the point be in the square?
1 answer:
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7.
remember
(ab)/(cd)=(a/c)(b/d)
we can split them up
and
(x^m)/(x^n)=x^(m-n)
=
9.
2 to 3
4(x-1)=15
to
4x-1=15
the distribuutive prperty
a(b-c)=ab-ac
what he did was
a(b-c)=ab-c
he did not distribute the 4 to the -1
4(x-1)+3=18
minus 3
4(x-1)=15
distribute 4 to x and -1
4x-4=15
add 4 to both sides
4x=19
divide by 4
x=19/4
remember
(ab)/(cd)=(a/c)(b/d)
we can split them up
and
(x^m)/(x^n)=x^(m-n)
9.
2 to 3
4(x-1)=15
to
4x-1=15
the distribuutive prperty
a(b-c)=ab-ac
what he did was
a(b-c)=ab-c
he did not distribute the 4 to the -1
4(x-1)+3=18
minus 3
4(x-1)=15
distribute 4 to x and -1
4x-4=15
add 4 to both sides
4x=19
divide by 4
x=19/4
Answer:
The graph of the triangle LMN and the image L'M'N' created by rotation of ΔLMN through 180° made with MS Excel is attached
The transformation involved in the 180° rotation of ΔLMN to create ΔL'M'N' includes;
The changing of the signs of the <em>x</em> and y-values of the coordinates of the vertices ΔLMN to get the corresponding <em>x</em> and y-values of the coordinates of the vertices of ΔL'M'N' as follows;
Before, rotation
The coordinates of the vertices of ΔLMN are; L(3, 3), M(9, 9), and N(9, 3)
After 180° rotation
The coordinates of the vertices of the image of ΔLMN, which is ΔL'M'N' are; L'(-3, -3), M'(-9, -9), and N'(-9, -3)
Therefore, the image of ΔLMN, ΔL'M'N' is located in the third quadrant, while the preimage ΔLMN is in the first quadrant
Part B
The lines drawn through L and L' and through M and M' are colinear lines
Part C
The lines dawn through points N and N' will not pass through the same line as the lines through L and L' and through M and M', because the three points are not colinear
Step-by-step explanation:
