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Liula [17]
3 years ago
5

Write the standard equation for the circle.

Mathematics
2 answers:
IrinaVladis [17]3 years ago
5 0
Im not sure but try
C. (x – 10)2 + (y + 6)2 = 36
standard form is (x-x1)^2 + (y-y1)^2=r^2.
nikdorinn [45]3 years ago
5 0

Answer:

i would do c to

Step-by-step explanation:

You might be interested in
Please help asap!!!!!!!
koban [17]

Answer:

-2

Step-by-step explanation:

7 0
2 years ago
Which system has no solutions?
ale4655 [162]

Answer:

the answer is C. x<3 x<1 that is the answer

5 0
3 years ago
Question 3, help please!
White raven [17]

The answer is not defined.

Explanation:

The given matrix is $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$

The matrix $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$ has dimensions 2\times 2

This means that the matrix has 2 rows and 2 columns.

Also, the matrix $\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$ has dimensions 2\times1

This means that the matrix has 2 rows and 1 column.

Since, the matrices can be added only if they have the same dimensions.

In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.

Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.

Hence, the addition of these two matrices is not defined.

4 0
3 years ago
What is the area of the figure below?
Troyanec [42]

Answer:

The area of the figure is 7.5 m².

Step-by-step explanation:

Given the lengths of diagonals

  • 2.5 m
  • 6 m

The area of the given figure can be computed by multiply the lengths of the diagonals and then divide by 2.

so

Area = (2.5 × 6 ) ÷ 2

        = 15 ÷ 2

        = 7.5 m²

Therefore, the area of the figure is 7.5 m².

3 0
3 years ago
What are the relative frequencies, to the nearest hundredth, of the rows of the two way table?
Nookie1986 [14]

Answer:            A         B

Group A        0.25      0.75

Group B        0.45      0.55

Step-by-step explanation:

Since we have given that

Number of people of A in Group A = 15

Number of people of B in Group A = 45

Number of people of A in Group B = 20

Number of people of B in Group B = 25

Total number of people in Group A = 15+45 = 60

Total number of people in Group B = 20+25 = 45

So, Relative frequencies will be given  below:

Relative frequency of A in Group A is given by

\frac{15}{60}=0.25

Relative frequency of B in Group A is given by

\frac{45}{60}=0.75

Relative frequency of A in Group B is given by

\frac{20}{45}=0.45

Relative frequency of B in Group B is given by

\frac{25}{45}=0.55

Hence,             A         B

Group A        0.25      0.75

Group B        0.45      0.55

5 0
3 years ago
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