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Ket [755]
3 years ago
10

An orbital of an atom is defined as the most probable location of(1) an electron (2) a neutron (3) a positron (4) a proton

Chemistry
2 answers:
Montano1993 [528]3 years ago
5 0

Answer: option (1) an electron.


Justification:


1) The plum pudding model of the atom conceived by the scientist J.J. Thompson, described the atom as a solid sphere positively charged with the electrons (particles negatively charged) embedded.


2) The next model of the atom, developed by the scientist Ernest Rutherford, depicted the atom a mostly empty space with a small dense positively charged nucleous and the electrons surrounding it.


3) Then, Niels Bhor came out with the model of electrons in fixed orbits around the nucleous, just like the planets orbit the Sun. So, the path followed by the electrons were orbits.


4) The quantum model of the atom did not place the electrons in fixed orbits around the nucleous but in regions around the nucleous. Those regions were named orbitals. And they are regions were it is most probable to find the electron, since it is not possible to tell the exact position of an electron.


As per this model, the electron has a wave function associated. The scientist Schrodinger developed the wave equation which predicts the location of the electron as a probability.


The orbitals are those regions were it is most likely to find the electron. Those regions are thought as clouds of electrons.

Doss [256]3 years ago
5 0
An orbital of an atom is defined as the most probable location of an Electron.
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your speed?

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8 0
3 years ago
4. How many molecules are there in 450.0 g of Na2SO4? (
vovikov84 [41]

Answer:16.02x1023 molec, Na₂SO4 = 119x1024 | 142.05g Na25041 Imol Naz Soy lec Na.

Explanation:

16.02x1023 molec, Na₂SO4 = 119x1024 | 142.05g Na25041 Imol Naz Soy lec Na.

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3 years ago
Which gas law states its correct correlation between its variables? Boyle's Law, P1 = V2 Charles's Law, Pı : Vi Boyle's Law, Pi
r-ruslan [8.4K]

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5 0
3 years ago
A bottle contains 2.5 moles of KOH dissolved in water, and the molarity of the solution is 0.16 M.
alexdok [17]

Answer:

V = 15.6 L

Explanation:

Hello there!

In this case, according to the definition of molarity in terms of the moles of solute divided by the volume of the solution, it is possible for us to write:

M=n/V

Thus, given the moles and concentration of the solution, we can find the volume as shown below:

V=n/M

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7 0
3 years ago
If 2.06 mL of seawater contains about 0.446 moles of gold, how many atoms of gold are in that volume of seawater?
Alborosie

Answer:

2.69 x 10²³ atoms

Explanation:

Given parameters:

Volume of sea water = 2.06mL

number of moles of gold = 0.446moles

unknown:

Number of atoms in the sea water

Solution:

The mole is a convenient unit of measuring quantities of particles. In a mole we have 6.02 x 10²³particles.

The mole can be defined as the amount of a substance contained in Avogadro's number of particles which is 6.02 x 10²³particles.

Here, the particles we want to determine is the number of atoms:

Number of atoms is given as:

   Number of gold atoms = number of moles of gold x 6.02 x 10²³

  Number of gold atoms = 0.446 x 6.02 x 10²³ = 2.69 x 10²³ atoms

5 0
4 years ago
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