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evablogger [386]
3 years ago
6

What is absolute zero? A) The temperature at which the particles of matter are at their lowest energy points. B) The temperature

at which the particles of matter are at their highest energy points. C) Other _______________
Chemistry
1 answer:
Alja [10]3 years ago
7 0

Answer:

A) The temperature at which the particles of matter are at their lowest energy points.

Explanation:

Absolute temperature refers to the lowest  possible temperature. At this state,  no heat energy remains in the substance; the energy of the particles are at their lowest energy points.

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. How many grams of Na2SO4 are required to make 2700 mL of a 2.0 M solution?
ratelena [41]

Answer:

Explanation:

From the net ionic equation

Ba2+(aq) + SO42-(aq) ==> BaSO4(s) we see that 1 mole Ba2+ reacts with 1 mole SO42- to -> 1 mol BaSO4

Find moles of Ba2+ used: 0.250 moles/L x 0.0323 L = 0.008075 moles Ba2+

Find moles SO42- present: 0.008075 moles Ba2+ x 1 mol SO42-/1 mol Ba2+ = 0.008075 mol SO42-

Find mass of Na2SO4 present: 0.008075 mol SO42- x 1 mol Na2SO4/1 mol SO42- x 142.04 Na2SO4/mole = 1.14698 g = 1.15 g Na2SO4 (to 3 significant figures)

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Carbon dioxide and water react to form methanol and oxygen, like this:
fredd [130]

Answer:

24x10³

Explanation:

2CO₂(g) + 4H₂O(g) → 2CH₃OH(l) + 3O₂ (g)

The equilibrium constant for this reaction is:

Kc = \frac{[O_2]^3}{[CO_2]^2[H_2O]^4}

The expression of [CH₃OH] is left out as it is a pure liquid.

Now we <u>convert the given masses of the relevant species into moles</u>, using their <em>respective molar masses</em>:

  • CO₂ ⇒ 3.28 g ÷ 44 g/mol = 0.0745 mol CO₂
  • H₂O ⇒ 3.86 g ÷ 18 g/mol = 0.214 mol H₂O
  • O₂ ⇒ 2.80 g ÷ 32 g/mol = 0.0875 mol O₂

Then we calculate the concentrations:

  • [CO₂] = 0.0745 mol / 7.5 L = 0.0099 M
  • [H₂O] = 0.214 mol / 7.5 L = 0.0285 M
  • [O₂] = 0.0875 mol / 7.5 L = 0.0117 M

Finally we <u>calculate Kc</u>:

  • Kc = \frac{0.0117^3}{0.0099^2*0.0285^4} = 24x10³

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