Qc < Kc, the reaction proceeds from left to right to reach equilibrium
<h3>Further explanation
</h3>
Given
K = 50.2 at 445°C
[H2] = [I2] = [HI] = 1.75 × 10⁻³ M At 445ºC
Reaction
H2(g) + I2(g) ⇔2HI(g)
Required
Qc
Solution
Qc for the reaction
![\tt Qc=\dfrac{[HI]^2}{[I_2][H_2]}\\\\Qc=\dfrac{(1.75.10^{-3})^2}{1.75.10^{-3}\times 1.75\.10^{-3}}=1](https://tex.z-dn.net/?f=%5Ctt%20Qc%3D%5Cdfrac%7B%5BHI%5D%5E2%7D%7B%5BI_2%5D%5BH_2%5D%7D%5C%5C%5C%5CQc%3D%5Cdfrac%7B%281.75.10%5E%7B-3%7D%29%5E2%7D%7B1.75.10%5E%7B-3%7D%5Ctimes%201.75%5C.10%5E%7B-3%7D%7D%3D1)
Qc < Kc ⇒ reaction from left(reactants) to right (products) (the reaction will shift on the right) until it reaches equilibrium (Qc = Kc)
Answer to the question
D. Petroleum
The answer is D) Electromagnetic energy. This is not a type of energy that occurs when a vehicle is moving.
I believe the compound is Phosphorus pentoxide
Answer:
Since HCl is a strong acid, it completely ionizes, and the pH of HCl in solution can be found from the concentration (molarity) of the H+ ions, by definition equal to 0.100 M. (The conjugate base of the acid, which is the chloride ion Cl–, would also have a concentration of 0.100 M.) The pH is thus –log(0.100) = 1.000.
Explanation:
