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evablogger [386]

3 years ago

6

What is absolute zero? A) The temperature at which the particles of matter are at their lowest energy points. B) The temperature

at which the particles of matter are at their highest energy points. C) Other _______________

1 answer:

Alja [10]3 years ago

7 0

Answer:

A) The temperature at which the particles of matter are at their lowest energy points.

Explanation:

Absolute temperature refers to the lowest possible temperature. At this state, no heat energy remains in the substance; the energy of the particles are at their lowest energy points.

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What words do scientist use to classify their ideas?

Nady [450]

Answer:

taxonomy

Explanation:

6 0

4 years ago

Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,

djverab [1.8K]

<u>Answer:</u> The reaction proceeds in the forward direction

<u>Explanation:</u>

For the given chemical equation:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

Relation of $K_p\text{ with }K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta n_g}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = $6.5\times 10^4$

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $35^oC=[35+273]K=308K$

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43$

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

The expression of $Q_p$ for above equation follows:

$Q_p=\frac{(p_{NOCl})^2}{p_{Cl_2}\times (p_{NO})^2}$

We are given:

$p_{NOCl}=1.76atm$

$p_{NO}=1.01atm$

$p_{Cl_2}=0.42atm$

Putting values in above equation, we get:

$Q_p=\frac{(1.76)^2}{0.42\times (1.01)^2}=7.23$

We are given:

$K_p=1583.43$

There are 3 conditions:

When $K_{p}>Q_p$ ; the reaction is product favored.
When $K_{p}$ ; the reaction is reactant favored.
When $K_{p}=Q_p$ ; the reaction is in equilibrium

As, $K_p>Q_p$ , the reaction will be favoring product side.

Hence, the reaction proceeds in the forward direction

4 0

3 years ago

When a nitrogen atom becomes an ion, the atom becomes a... A. Negative ion with a radius smaller than the radius of the atom B.

mr Goodwill [35]

Answer:

B. Negative ion with a radius larger than the radius of the atom

Explanation:

When a negative ion is formed, electrons are added to the atom. As electrons are added to the atom, the size of the electron cloud increases accordingly.

As a result of this, a negative ion is always larger than its corresponding atom. Hence, nitrogen ion must be larger than the nitrogen atom based on the facts stated above.

3 0

3 years ago

If 3.289 x 10^23 atoms of potassium react with excess water, how many grams of hydrogen gas would be produced?

GarryVolchara [31]

Answer:

The amount in grams of hydrogen gas produced is 0.551 grams

Explanation:

The parameters given are;

Number of atoms of potassium, aₙ = 3.289 × 10²³ atoms

Chemical equation for the reaction is given as follows;

2K + 2H₂O $\rightarrow$ KOH + H₂

Avogadro's number, $N_A$ , regarding the number of molecules or atom per mole is given s follows;

$N_A$ = 6.02 × 10²³ atoms/mole

Therefore;

The number of moles of potassium present = 3.289 × 10²³/(6.02 × 10²³) = 0.546 moles

2 moles of potassium produces one mole of hydrogen gas, therefore;

1 moles of potassium produces 1/2 mole of hydrogen gas, and 0.546 moles of potassium will produce 0.546/2 moles of hydrogen which is 0.273 moles of hydrogen gas

The molar mass of hydrogen gas = 2.016 grams

Therefore, 0.273 moles will have a mass of 0.273×2.016 = 0.551 grams.

The amount in grams of hydrogen gas produced = 0.551 grams.

8 0

3 years ago

Why do A and T (and G and C) pair in a DNA double helix?

Usimov [2.4K]

I just took a quiz on this! It's D!

3 0

3 years ago