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amm1812
3 years ago
14

How many grams are in 2.5 moles of N2? (2 decimal places)

Chemistry
1 answer:
Leokris [45]3 years ago
3 0

Answer: How many grams are in 2.5 moles of N2?

Explanation: 1 mole is equal to 1 moles N2, or 28.0134 grams.

 One mole of N2 molecules would have a mass of 2 X 14.01 g = 28.02 g.

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What is the total number of electrons in a<br> Mg2+ ion?(1) 10 (3) 14<br> (2) 12 (4) 24
Citrus2011 [14]
The answer is (1) 10. The protons of Mg atom is 12. So the Mg atom has 12 electrons. The Mg2+ ion has lost two electrons so it has two positive charge. Then the answer is 10 electrons.
5 0
3 years ago
The molar volume of oxygen,O2, is 3.90 dm3 mol-1 at 10.0 bar and 200 degree centigrade. Assuming that the expansion may be trunc
schepotkina [342]

Answer:

B = - 0.0326 dm³/mol

Explanation:

virial eq until second term:

  • PVm = RT [ 1 + B/Vm ]

∴ P = 10 bar * (atm/ 1.01325 bar) = 9.869 atm

∴ T = 200°C = 473 K

∴ Vm = 3.90 dm³/mol

∴ R = 0.08206 dm³.atm/K.mol

⇒ PVm / RT = 1 + B/Vm

⇒ ((9.869 atm)*(3.90 dm³/mol)) / ((0.08206 dm³.atm/mol.K)*(473K)) = 1 + B/Vm

⇒ 0.99164 = 1 + B/Vm

⇒ B/Vm = - 8.357 E-3

⇒ B = (3.90 dm³/mol)*( - 8.357 E-3 )

⇒ B = - 0.0326 dm³/mol

4 0
3 years ago
What would make oppositely charged objects attract each other more?
zlopas [31]

Answer: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object.

Explanation:

edge

4 0
2 years ago
Read 2 more answers
Please match the orbital type with the correct number of orbitals
saul85 [17]
Hi there!

p = e-3
s = f-1
f = i-7
d = g-5

Hope that helps!
Brady
7 0
3 years ago
Problem 12.002 the molar analysis of a gas mixture at 30°c, 2 bar is 40% n2, 50% co2, 10% ch4. determine
andreev551 [17]
The problem is incomplete. However, there can only be two probable questions for this problem. First, you can be asked the individual partial pressures of each gas. Second, you can be asked the volume occupied by each gas. I can answer both cases for you.

1.

Let's assume ideal gas.
Pressure for N₂: 2 bar*0.4 = 0.8 bar
Pressure for CO₂: 2 bar*0.5 = 1 bar
Pressure for CH₄: 2 bar*0.1 = 0.2 bar

2. For the volume, let's find the total volume first.

V = nRT/P = (1 mol)(8.314 J/mol-K)(30 +273 K)/(2 bar*10⁵ Pa/1 bar)
V = 0.0126 m³
Hence,
Volume for N₂: 0.0126 bar*0.4 = 0.00504 m³
Volume for CO₂: 0.0126*0.5 = 0.0063 m³
Volume for CH₄: 0.0126*0.1 = 0.00126 m³
3 0
3 years ago
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