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Ede4ka [16]
3 years ago
6

without any natural predators rabbits can grow at a rate of 25% each year, if 6 rabbits were introduced into an area how many ra

bbits can be expected to exist after 10 years
Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0
The growth rate is 25%

Initial population, P = 6
Growth rate, r = 25% = 25/100 = 0.25
Number of years, t = 10
Final population, A = ?

A = P * (1 + r) ^t

= 6 * (1 + 0.25) ^10
= 6 * 1.25^10
= 6 * 9.31
= 55.86
Approximately 56

Therefore, approximately 56 rabbits can be expected to exist after 10 years
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To compare this two sets of data, you need to use a t-student test:

You have the following data:

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You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.



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3 years ago
Which of the following expressions is a polynomial?
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