Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Polynomial requirements
1. never divide by a placeholder
2. variable exponent has to be a whole number
3. can't have infinte terms
by 1. we eliinate 2nd one
by 2. we eliminate first one (√x=x^1/2) and 3rd one because it has an exponent in placeholder
thie leaves us with last one
f(x)=2x³-5x⁵-(2/9)x²+9
last one is answer
Answer: $266,000
Explanation: $256,000 + $10,000 = $266,000
Answer:
Because square root is essentially the same thing as the power to a half
sqrt(x) is the same as (x)^1/2