Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
Answer:x=0
Step-by-step explanation:
subtract 3 from both sides
3=3=x+3-5x-3
simplify
0=x-5x
switch sides
x-5x
add similar elements ; x-5x=-4x
-4x=0
divided both side by -4
-4x/-4 . = . 0/-4
=0
Answer:
yes, $20.
Step-by-step explanation:
If you draw a line through the points it makes a straight line, so it is linear. And you get $20 by dividing $100 per the 5 people.
Is this a year 9 question and if yes I do not have a clue lol
Answer:
27/100
Step-by-step explanation:
It's in the hundreths,
so we just put 27 over 100
