Answer: The balls would hit the ground at the same time.
Explanation: Since there is no air resistance, we would put Galileo's experiment into motion. Galileo once performed an experiment of dropping two items, with different masses, from the tower of Pisa. Since there was no air resistance, the balls hit the ground at the same time. In this problem, the balls are "free-falling." Freefall is a term used in Physics to describe the motion of a falling object experiencing only the acceleration due to gravity. g=9.8 m/s^2 (acceleration due to gravity.) 9.8 will always be the acceleration in a free fall event like this with no air resistance, since Gravity remains constant.
Newton's second law of motion states that F=ma, (force is equal to mass times acceleration), but since Newton also states that f=mg, we can conclude that ma=mg. Stating that no matter what the mass of the object is, both of the objects will fall at the same time with the same velocity.
the answer is C. all of the biotic and abiotic components of the great lakes region
Answer:
The velocity and translational kinetic energy of the acorn when hitting the ground are approximately 19 meters per second and 3 joules, respectively.
Explanation:
Let suppose that the acorn is a conservative system. By Principle of Energy Conservation, we understand that initial potential gravitational potential energy (
), in joules, which is related to initial height above the ground, is equal to the final translational kinetic energy (
), in joules, related to the instant just before hitting the ground. Let suppose that ground has a height of zero. That is:
(1)
(1b)
Where:
- Mass, in kilograms.
- Gravitational acceleration, in meters per square second.
- Height, in meters.
- Speed, in meters per second.
If we know that
,
and
, then the velocity and the translational kinetic energy of the acorn just before hitting the ground is:





The velocity and translational kinetic energy of the acorn when hitting the ground are approximately 19 meters per second and 3 joules, respectively.
Explanation:
here,load=100N
effort=200N
distance travelled by load=2cm
distance travelled by effort=10cm
Now, output work=L*Ld
=100*2
=200g
Again,
input work =E*Ed
200*10
2000j
again, efficiency = output work/input work*100%
200/2000*100%
=10%
please don't forget to write symbol
Answer:
The value is 
Explanation:
From the question we are told that
The first point charge is 
The second point charge is 
The repulsive force exerted is 
Generally the repulsive force exerted is mathematically represented as

Here k is the coulomb constant with a value 
So

=> 
=> 