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2 years ago

How do stairs reduce the

Physics

1 answer:

maw [93]2 years ago

5 0

It’s B. Require a small force over a long distance

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The process of submerging an object to determine its volume is called

emmasim [6.3K]

Answer: By Contributor. Measuring the volume of an irregularly shaped object using geometry is often difficult and complicated. The easiest way to do this is by using the water displacement method. Often taught in chemistry or other science classes, this method is known for its simplicity and accuracy.

Explanation:

3 0

2 years ago

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What is the danger to spacecraft and astronauts from micrometeoroids?

Sloan [31]

Answer:

Suppose the micrometeoroid weighed 1 g = .001 kg

Suppose also the spacecraft were moving at 18,000 mph (1.5 hrs per rev)

Usually, the smaller particle would be moving but for simplicity suppose that it were stationary wrt the ground

v = 18000 miles / hr * 1500 m/mile / 3600 sec/hr = 7500 m/s

KE = 1/2 * .001 kg * (7500 m)^2 = 28,125 Joules

One can see that 28000 Joules could be damaging amount of energy

7 0

3 years ago

(II) How much work did the movers do (horizontally) pushing a 46.0-kg crate 10.3 m across a rough floor without acceleration, if

Gwar [14]

Answer:

2324 J

Explanation:

The formula for work is:

$W=F*d$

where $F$ is the force applied, and $d$ is the distance moved, in this case $d=10.3m$

and we need to find $F.$

Since the crate is not moving up or down, we conclude that the <u>normal force must be equal to the weight </u>of the object:

$N=w$

where $N$ is the normal force and $w$ is the weight, which is: $w=mg$ , where g is the gravitational acceleration $g=9,81m/s^2$ and $m$ is the mass $m=46kg$ .

---------

Thus the normal force is:

$N=mg$

Now, the force due to the friction is defined as:

$f=\mu N=\mu mg$

where $\mu$ is the coefficient of friction, $\mu =0.5$

So, for the crate to move, the force applied must be equal to the frictional force:

$F=f\\F=\mu mg$

And now that we know the force we can calculate the work:

$W=F*d\\W=\mu mg*d$

substituting known values:

$W=(0.5)(46kg)(9.81m/s^2)(10.3)\\W=2324J$

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3 years ago

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Determine the kinetic energy of 650 kg roller coaster car that is moving with a speed of 20.0 miles per second?

mestny [16]

Answer:Ek=673.109 kJ

Explanation:

Use equation for Kinetic energy: Ek=m*V²/2

m=650 kg (mass of roller coaster)

V=20.0Miles/s=20.0*1.609m/s=32.18m/s

Ek=m*V²/2

Ek=650kg*(32.18m/s)²

Ek=(650kg*1053.55m²/s²)/2

Ek=673 108.8 J

Ek=673.109 kJ

4 0

3 years ago

Un auto si muove lungo una strada rettilinea

Valentin [98]

Answer:

Un'auto si muove lungo un percorso rettilineo con velocità variabile come mostrato in figura. Quando l'auto è in possesso di A, la sua velocità è 10 ms-1 e quando è in posizione B, la sua velocità è 20 ms-1. Se l'auto impiega 5 secondi per spostarsi da A a B, trova l'accelerazione dell'auto.

Explanation:

8 0

3 years ago