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vovangra [49]
3 years ago
12

Please helo me to 1st question​

Physics
1 answer:
k0ka [10]3 years ago
6 0

Explanation:

6 min in seconds:

6×60

<h2><u>360</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u><u> </u></h2><h2 /><h2 />

6 min in hours:

<h2><u>0</u><u>.</u><u>1</u><u> </u><u>hours</u></h2>
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Write examples of adaptation in mangrove .? <br>what are the adaptation of rainforest.?​
Sergio039 [100]

Answer:

example of adaptation in mangrove

Mangroves are salt-tolerant trees, also called halophytes, and are adapted to life in harsh coastal conditions. They contain a complex salt filtration system and complex root system to cope with salt water immersion and wave action. They are adapted to the low oxygen conditions of waterlogged mud.

adaptation of rainforest

Many animals have adapted to the unique conditions of the tropical rainforests.

hope this can help you

6 0
3 years ago
Convert 0.000238 m to cm
enot [183]

Answer:

0.0238 centimetre

Explanation:

multiply the length value by 100

3 0
3 years ago
When you hold a cold glass of water in your warm hand, which way does the heat flow ?
Tanya [424]

Heat flows naturally from a warmer object (higher energy) to a cooler one (lower energy).

6 0
3 years ago
A. The potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J. Find by
valina [46]

a. The spring is compressed  by  0.174 m.

b.  The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.

c. The horizontal velocity of the dart at that time is  13.74 m/s.

d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.

PE  of spring = 1/2 kx²

Put the values, we get

P.E = 0.940 = 1/2 x 62 x²

x = 0.174 m

Thus, the spring is compressed by 0.174 m.

b. Given is a 0.010 kg dart is fired straight up.

The vertical height is find out by

0.940 J = (0.010 kg) (9.8 m/s²) h

h = 9.6 m

Thus, the vertical distance the dart travels from its position is 9.6 m

c. From the conservation of energy principle, total mechanical energy is conserved.

1/2 mv² =mgh

v = √2gh

Plug the values, we get

v = √2 x 9.8x 9.6

v = 13.74 m/s

Thus, the horizontal velocity is  13.74 m/s.

d.  Time that dart spends in air, t = √2h/g

t = √(2x9.6)/9.81

t = 1.4 s

The horizontal distance from the equilibrium position at which the dart hits the ground.

Horizontal distance = (Velocity on x direction) x time

Horizontal distance = 13.74 m/s x 1.4s

Horizontal distance = 19.236 m

Thus, the horizontal distance is 19.236 m.

Learn more about potential energy.

brainly.com/question/24284560

#SPJ1

7 0
2 years ago
Failure to accomplish Erikson’s psychosocial task of late adulthood leads to despair.
Y_Kistochka [10]
False is the answer
6 0
3 years ago
Read 2 more answers
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