Answer:
D. 43° 52`
Explanation:
A bearing is an angle, measured clockwise from the north direction. When solving a bearing problem, it is good to represent the bearings in the given question with diagram.
The diagrammatically representation of the bearing of lines A and B, 16° 10` and 332° 18` respectively given in the question is shown in the figure attached.
At Point A, we will calculate angle ∠BAO.
Calculating the angle ∠BAO
∠BAO = 90° - 16° 10`
= 73° 50`
At Point B, we will calculate angle ∠ABO.
Calculating the angle ∠ABO
∠ABO = 332° 18` - 270° 0`
= 62° 18`
At Point O, we will calculate the include angle ∠BOA.
Calculating the angle ∠BOA
∠BAO + ∠ABO + ∠BOA = 180° (sum of angles in a triangle)
73° 50` + 62° 18` + ∠BOA = 180°
136° 8` + ∠BOA = 180°
∠BOA = 180° - 136° 8`
∠BOA = 43° 52`
The value of the included angle BOA is 43° 52
The constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².
<h3> Constant angular acceleration</h3>
Apply the following kinematic equation;
ωf² = ωi² - 2αθ
where;
- ωf is the final angular velocity when the centrifuge stops = 0
- ωi is the initial angular velocity
- θ is angular displacement
- α is angular acceleration
ωi = 3400 rev/min x 2π rad/rev x 1 min/60s = 356.05 rad/s
θ = 52 rev x 2π rad/rev = 326.7 rad
0 = ωi² - 2αθ
α = ωi²/2θ
α = ( 356.05²) / (2 x 326.7)
α = 194.02 rad/s²
Thus, the constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².
Learn more about angular acceleration here: brainly.com/question/25129606
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The answers To your question is c