All methods are supposed to be correct in most if not all situations and it should not matter if you use a different method given the options
1/10 currant
2/5 is cherry × 2 to get it out of 10
so 4/10 (cherry) + 1/10 (currant) = 5/10 so 5 raisins
Leannie bought 5 of Dr. Mumin’s book and 3 of Dan Moyer’s book
The fence must have two sides of length 45.45 ft and two sides of length 14.63
To cover each of 45.45 ft long side, he will need 45.45 / 2 = 22.7 slats which approximates to 23. So, they are 2 * 23 = 46 slats.
To cover each of 14.63 ft sides, he will need 14.63 / 2 = 7.3 which approximates to 8 (to not leave any spaces between each slat). So, they are 2 * 8 = 16 slats.
That makes 46 + 16 = 62 slats.
Answer: around 62 slats.
Answer:
The nth term of an AP will be 27 -7n.
Step-by-step explanation:
First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5
Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .
Here first term is 26 .
And the nth term of an AP is given by ,
★ T_n = a + ( n - 1) d
<u>Subst</u><u>ituting</u><u> respective</u><u> values</u><u> </u><u>,</u>
⇒ T_n = a + ( n - 1 )d
⇒ T_n = 26 + (n - 1)(-7)
⇒ T_n = 26 -7n+1
⇒ T_n = 27 - 7n
<h3>
<u>Hence </u><u>the</u><u> </u><u>nth</u><u> </u><u>term</u><u> of</u><u> an</u><u> </u><u>AP</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>found </u><u>using </u><u>T_</u><u>n</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u><u>-</u><u> </u><u>7</u><u>n</u><u>. </u></h3>
