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liberstina [14]
2 years ago
10

there are 12 boys and 13 girls in a class. There are 10 boys and 15 girls in a second class. what is the probability that both s

tudents will be boys from either class?
Mathematics
1 answer:
o-na [289]2 years ago
3 0
22 out of 50 would be the answer
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On a graph what are the points on the equation 3x+2y=6
Igoryamba
(4,-3) hope this helps

4 0
3 years ago
a sports team donates 157 tickets to a sporting event,with tickets to be shared equally among 9 classrooms.How many tickets does
Valentin [98]

Answer:

Each class should get 17 tickets. 4 tickets will be left over.

Step-by-step explanation:

157/9=17.444... -> 17 per class

17 x 9 = 153

157-153= 4 left

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8 0
3 years ago
Find the sum of the odd integers between 24 and 50
morpeh [17]

Answer:

  481

Step-by-step explanation:

There are several ways you can get there.

1. There are only 13 numbers, so you can write them down and add them up.

  25 + 27 + 29 + ... + 47 + 49 = 481

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2. You can use the formula for the sum of an arithmetic sequence. This one has a starting value of 25, an ending value of 49, and 13 terms.

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3. You can use a formula for the terms of the series and evaluate the sum.

  an = 25 +2(n -1) = 2n +23

\sum\limits_{n=1}^{13}{(2n+23)}=2\sum\limits_{n=1}^{13}(n)+\sum\limits_{n=1}^{13}{(23)}=2\dfrac{13\cdot 14}{2}+13\cdot 23=481

4 0
2 years ago
Pleasee help I need to pass this class!!!! Solve for x
Nady [450]
C. X = 16

To solve, add 7 to both sides and multiply by the reciprocal of \frac{-9}{8}, \frac{-8}{9}.

( \frac{-9}{8} ) X - 7 = -25&#10;&#10;&#10;
( \frac{-9}{8} ) X = -18
X = 16
5 0
3 years ago
Read 2 more answers
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