Answer:
your answer is down below
Step-by-step explanation:
Answer:
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error:

For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is
We need a sample size of at least n, in which n is found M = 0.04.







With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Answer:
last week = 150 minutes
this week = 162 minutes
changes = 162-150
= 12 minutes
percentage of changes = (12/150) × 100
= 8%
4n-2n=6
2n=6
n=6/2
n=3
Your answer is C. 3
Answer:
Equation: 3.75x+58=226.75
Step-by-step explanation:
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