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Aloiza [94]
3 years ago
9

Find the coordinates of the image under the transformation (x – 4, y + 6) for ∆XYZ at X(-6, 1), Y(4, 0), Z(1, 3)

Mathematics
2 answers:
Afina-wow [57]3 years ago
6 0

Answer:

I think b

Step-by-step explanation:

I prefer B but it also might be D

Mama L [17]3 years ago
5 0

Answer:

4444444

Step-by-step explanation:

ffcccfcdxcvbnbvfdsdfghbjnmndsdfghjk i dont know step one multipy the 3 from the 4 divide thevanswer which we dont know

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A student is attempting to solve the equation below for the variable x. Which of the statements below best applies to the mathem
Elanso [62]
Please answer please please thank you
7 0
3 years ago
Simplify to create an equivalent expression. -k-(-8k+7)
const2013 [10]

Answer:

7k -7

Step-by-step explanation:

-k-(-8k+7)

Distribute the minus sign to all terms in the parentheses

-k--8k-7

Ad negative negative is a positive

-k + 8k -7

Combine like terms

7k -7

8 0
3 years ago
diketahui akar akar persamaan kuadrat 2x^2-9x + 7 = 0 adalah x1 dan x2. nilai dari x1^2 + x2^2- 4x1x2 adalah...
Leviafan [203]
<span>jika xy = 0 , kemudian menganggap x dan y = 0

faktor 2x^2-9+7
(2x-2)(x-7)=0

2x-2=0
2x=2
x=1

x-7=0
x=7

</span><span>jika 1 = x1 dan 7 = x2 maka jawabannya adalah 1^2+7^2-4(1)(7)=22
</span>
jika 7 = x1 dan 1 = x2 maka jawabannya adalah
7^2+7^2-4(7)(1)=22

<span>jawabannya adalah 22</span>


6 0
3 years ago
Leela made goody bags for her party and put 5 pieces of candy in each bag. She bought gummies and chocolates yo put in het goody
slavikrds [6]

Answer:

4 ways

Step-by-step explanation:

1 gummy 4 chocolates

2 gummy 3 chocolates

3 gummy 2 chocolates

4 gummy 1 chocolates

This is what i think the answer is hope it helps

5 0
3 years ago
-x + 2y = 3<br> 2x – 3y = -6
s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>Equating</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

4 0
3 years ago
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