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JulsSmile [24]
3 years ago
7

10x^2-3x-27 Factor the trinomial

Mathematics
1 answer:
noname [10]3 years ago
6 0

Answer:

(2x+3)(5x-9)

Step-by-step explanation:

10x^2-3x-27

10x^2 + 15x - 18x - 27

(5x)(2x+3)-9(2x+3)

(2x+3)(5x-9)

Hope this helps!

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I have these fractions: 4/5 , 5/6 , and 3/12. Can someone help to put them in order from LEAST to GREASTEST?
vodomira [7]

The answer is 5/6, 4/5, and 3/12.  All you needed to do was change the fraction into decimals.

5 0
3 years ago
VERY IMPORTANT... write the equation of the line that has a y intercept of (0.4) and a slope of -3/2​
shutvik [7]

Answer:

y = -3/2 x + 4

Step-by-step explanation:

y-4 = -3/2 ( x-0)

y = -3/2 x + 4

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The measure of a square side is 1.2 feet what is the perimeter of the square inches
lilavasa [31]

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Lonna had 30 minutes to do a three-problem quiz. She spent 11 minutes on question A and 4
STatiana [176]

Answer:

She had 15 minutes left.

Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
A<br> Find tan a.<br> r<br> √5,-√7)<br> ✓[?<br> Enter
Virty [35]

Answer:

tan(\alpha)=-\frac{\sqrt{35}}{5}

Step-by-step explanation:

Tan can be defined as: \frac{sin(\theta)}{cos(\theta)} as it simplifies to opposite/adjacent. If you know a bit about the unit circle, you'll know that the x-coordinate is going to be cos(theta) and the y-coordinate is going to be sin(theta). Since the sin(theta) is defined as opposite/hypotenuse, and the hypotenuse = 1, so sin(theta) is defined as the opposite side, which is the y-axis. Same thing goes for cos(theta), except the adjacent side is the x-axis.

Using this we can define tan

sin(\alpha)=-\sqrt{7}\\cos(\alpha)=\sqrt{5}\\\\tan(\alpha)=-\frac{\sqrt{7}}{\sqrt{5}} * \frac{\sqrt{5}}{\sqrt{5}}\\tan(\alpha)=-\frac{\sqrt{7*5}}{5}\\tan(\alpha)=-\frac{\sqrt{35}}{5}\\

8 0
2 years ago
Read 2 more answers
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