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Furkat [3]
3 years ago
7

Can you please answer?

Mathematics
1 answer:
loris [4]3 years ago
4 0

Answer:

here here here here here here

wait wrong

hold up

edited

x-intercept:(4,0)

y-intercept:(0,-4)

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Y - wy = m (solve for w)<br><br><br>I need an answer ASAP.
wolverine [178]

answer:

w = (-m+y)/y

Step-by-step explanation:

y-wy = m

-wy = m-y

y = -(m-y)/w

wy= -m + y

w = (-m+y)/y

.

5 0
2 years ago
What are the coordinates of (-3,4) when it is reflected over the y-axis.
AysviL [449]

Answer:

D. (4,3)

Step-by-step explanation:

(-3,4)

Reflection in the y-axis:

Same y, -ve x

(3,4)

Reflection in y = x

(x,y) goes to (y,x)

(3,4) goes to (4,3)

3 0
3 years ago
Please help! Divide. Write the quotient in lowest terms.
Mekhanik [1.2K]
The correct answer for this would be 32/5
6 0
3 years ago
What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

7 0
3 years ago
Julian is using a biking app that compares his position to a simulated biker traveling Julian's target speed. When Julian is beh
zepelin [54]

Answer:

\large \boxed{\text{11 km/h}}

Step-by-step explanation:

1. The situation after 15 min:

(a) Distance travelled by simulated biker:

15 min =¼ h  

\text{Distance} = \dfrac{1}{4}\text{ h} \times \dfrac{\text{20 km}}{\text{1 h}} = \text{5 km}

(b) Distance travelled by Julian

Julian is 2¼ km behind  the biker. The distance he has travelled is (5 - 2¼) km

5 - 2¼ = 5 - ⁹/₄ = ²⁰/₄ - ⁹/₄ = ¹¹/₄ = 2¾

Julian has travelled 2¾ km in ¼ h.

2. Julian's average speed

\text{Speed} = \dfrac{\text{Distance}}{\text{Time}} = \dfrac{2\frac{3}{4}\text{ km}}{\frac{1}{4}\text{ h}} =\dfrac{11}{4}\text{ km}\times \dfrac{4}{\text{1 h}} = \textbf{11 km/h}\\\\\text{Julian's average speed is $\large \boxed{\textbf{11 km/h}}$}

7 0
3 years ago
Read 2 more answers
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