22.0. diameter times pie to get your answer then round to 1dp
Answer:
this is your answer.
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Answer:
Simplifying
lx2 + mx + n = 0
Solving
lx2 + mx + n = 0
Solving for variable 'l'.
Move all terms containing l to the left, all other terms to the right.
Add '-1mx' to each side of the equation.
lx2 + mx + -1mx + n = 0 + -1mx
Combine like terms: mx + -1mx = 0
lx2 + 0 + n = 0 + -1mx
lx2 + n = 0 + -1mx
Remove the zero:
lx2 + n = -1mx
Add '-1n' to each side of the equation.
lx2 + n + -1n = -1mx + -1n
Combine like terms: n + -1n = 0
lx2 + 0 = -1mx + -1n
lx2 = -1mx + -1n
Divide each side by 'x2'.
l = -1mx-1 + -1nx-2
Simplifying
l = -1mx-1 + -1nx-2
Step-by-step explanation:
Hope this helped you!
Answer:
Step-by-step explanation:
I am on the same question
Start with

We observe that both fractions are not defined if
. So, we will assume
.
We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

We multiply both sides by
:

We move everything to one side and solve the quadratic equation:

We check the solution:

which is true