Question

MATH HELP ASAP :( Write a polynomial f(x) that satisfies the given conditions. Express the polynomial with the lowest possible leading positive integer coefficient. Polynomial of lowest degree with lowest possible integer coefficients, and with zeros 9-41 and 0 (multiplicity 2).

Answer 1

Answer:

$f(x)=((x-9)^2+16)x^2$

$f(x)=x^4-18x^3+97x^2$

Step-by-step explanation:

If you want to, I could add the explanation as well. Just notify me.

Something really important I want to note is that since 9-4i is a zero, then 9+4i must must also be a zero.