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docker41 [41]
3 years ago
15

Plz help!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Goshia [24]3 years ago
3 0

Answer:

b) 95

Step-by-step explanation:

equation:

3 x 30 + 5

solve:

3 x 30 + 5 = 95

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Consider the following algebraic expression:--5x + 6Step 1 of 2: Identify the first term of the algebraic expression. Indicate w
Sunny_sXe [5.5K]

So,

Here we have the following algebraic expression:

-5x+6

The first term of this expression is -5x.

This term is clearly a variable term. The variable is x and its coefficient is -5.

5 0
1 year ago
José collects stamps. He has 7 used stamps for every 4 new stamps. If he has 28 new stamps, how many used stamps does he have?
jenyasd209 [6]

Answer:

José has 49 used stamps

Step-by-step explanation:

7 used stamps for every 4 new stamps

To solve this type of problem, we can use a ratio

7 : 4 ratio

He has 28 new stamps

7 : 4 = x : 28

Ratios can be written as fractions

\frac{7}{4} = \frac{x}{28}

Cross multiply

4x = 7(28) = 196

Divide by 4 on both sides

x = 49

Hope this helps :)

3 0
3 years ago
HELP ME PLEASEEEE!!!!ORDER THESE BY VALUE FROM LEAST TO GREATEST!!!
Advocard [28]

Answer: 5,15,20,25,45

Step-by-step explanation:

1st is 20, 2nd is 25, 3rd is 15, 4th is 45, 5th is 5

5 0
3 years ago
Find the median data 46,22,46,49,45,39,40,42,41,39,40,36
ddd [48]

Answer:

median is 40.5

Step-by-step explanation:

22, 36, 39, 39, 40, 40, 41, 42, 45, 46, 46, 49

half way between numbers in numerical order

lands between 40 and 41

40.5

7 0
2 years ago
Read 2 more answers
Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3
babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable z first.

Step 1:  She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9

Now, adding this to equation 1 will cancel out z terms.

12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4

Now, she need to make one more equation in x\ and \ y.

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21

Now, adding this to equation 2 will not cancel out z terms.

-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20

So, she makes mistake in step 2 as the z terms are not being cancelled.

6 0
3 years ago
Read 2 more answers
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