Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer:
Water is not wet, it makes things wet.
Answer:
B.
Step-by-step explanation:
First we must find the x and y intercepts for y = -2x - 4. The y-intercept is -4, since it is b in y = mx + b, but you can also find it by plugging in zero for x:

The x-intercept is found by plugging in zero for y:





The graph with an x-intercept of -2 and a y-intercept of -4 is C. Also, less than inequalities have the shading underneath the line, so we definitely know C is the answer.
Isolate the variable x.
1-2x=-x-3
1=x-3
x=4