keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above
![y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=y%20%3D%20%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B-%5Ccfrac%7B1%7D%7B3%7D%7Dx%2B5%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)

Any ratio simply takes the form (A/B)
Let throws = T , games = G
T = 36
G = 16
ratio of free throw to game = T/G
T/G = 36/16 = 9/4
Answer:
Use the Triangle exterior angle theorem. The definition of this theorem, is that the exterior angle you are solving for is the sum of the two opposite interior angles. Set the equation:
80 + x = 3x - 22
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract x and add 22 to both sides.
80 (+22) + x (-x) = 3x (-x) - 22 (+22)
80 + 22 = 3x - x
Simplify.
102 = 2x
Isolate the variable, x. Divide 2 from both sides.
(102)/2 = (2x)/2
x = 102/2
x = 51
Check. Plug in 51 to the equation given.
80 + x = 3x - 22
80 + (51) = 3(51) - 22
131 = 153 - 22
131 = 131 (True).
~
Answer:
5 inches
Step-by-step explanation:
we know that
The scale drawing is

using proportion find out the width of the great room on her plan

Answer:
option A. 3x - y = 2 and 3x - y = 1
Step-by-step explanation:
Using the rule of y-intercept which is the value of y when x equals 0
<u>Option A:</u> 3x-y=2 and 3x-y=1
y-intercepts will be ⇒ -2 and -1
<u>Option B:</u> 3x+y=2 and 3x-y=1
y-intercepts will be ⇒ 2 and -1
<u>Option C:</u> 3x-y=2 and 3x+y=1
y-intercepts will be ⇒ -2 and 1
<u>Option D:</u> 3x+y=2 and 3x+y=1
y-intercepts will be ⇒ 2 and 1
Comparing the results with the y-intercepts from the graph
From the graph the system of equation intersects with y-axis, (which mean x=0), at y = -2 , -1
So, the system which is represented by the graph is option A