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aev [14]
3 years ago
9

An architect is making a floor plan for an apartment. The floor plan will include a Great Room with a length of 30 feet and a wi

dth of 20 feet. On her floor plan, 1/4 inch will represent 1 foot of the room’s actual width. What will be the width of the Great Room, in inches, on her floor plan?
Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

5 inches

Step-by-step explanation:

we know that

The scale drawing is

\frac{1}{4}\ in : 1\ ft

using proportion find out the width of the great room on her plan

\frac{(1/4)}{1}\ \frac{in}{ft}=\frac{x}{20}\ \frac{in}{ft}\\\\x=20(1/4)\\\\x=5\ in

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F(g(x)) = [(-7x-8)/(x-1) - 8} / [(-7x - 8)/(x-1) + 7] =

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Answer:

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We can find the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496

And we can calculate the variance with this formula:

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And the deviation is:

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Step-by-step explanation:

For this case we have the following probability distribution given:

X          0            1        2         3        4         5

P(X)   0.031   0.156  0.313  0.313  0.156  0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

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\sum_{i=1}^n P(X_i) = 1

And P(X_i) \geq 0, \forall x_i

So then we have a probability distribution

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E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5

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And we can calculate the variance with this formula:

Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246

And the deviation is:

Sd(X) = \sqrt{1.246}= 1.116

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