![\qquad\qquad\huge\underline{{\sf Answer}}](https://tex.z-dn.net/?f=%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D)
Let's evaluate ~
![\qquad \sf \dashrightarrow \: 5(z + 4) + 5(2 - z)](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%205%28z%20%2B%204%29%20%2B%205%282%20-%20z%29)
![\qquad \sf \dashrightarrow \: (5 \cdot z) + (5\cdot4) + (5\cdot2) - (5\cdot z)](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20%285%20%5Ccdot%20z%29%20%2B%20%285%5Ccdot4%29%20%2B%20%285%5Ccdot2%29%20-%20%285%5Ccdot%20z%29)
![\qquad \sf \dashrightarrow \: 5z + 20 + 10 - 5z](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%205z%20%2B%2020%20%2B%2010%20-%205z)
![\qquad \sf \dashrightarrow \: 5z - 5z+ 20 + 10](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%205z%20%20-%205z%2B%2020%20%2B%2010)
![\qquad \sf \dashrightarrow \: 30](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%2030)
So, the equivalent expression is 30
20-1=19 hop this helps :)
Answer:
839393
Step-by-step explanation:
Answer: The square root of 140 is irrational.
Step-by-step explanation:
Take the square root of 140:
11.8321595662
This is an imperfect square root, and all imperfect square roots are irrational.
Given :
Square-based pyramid that has base edges measuring 6 units and lateral edges measuring 5 units.
To Find :
The total area, in square units, of the four triangular faces of a right.
Solution :
We know, area of square based prism is given by :
![A = a^2 + \dfrac{ah}{2}](https://tex.z-dn.net/?f=A%20%3D%20a%5E2%20%2B%20%5Cdfrac%7Bah%7D%7B2%7D)
Here, a is the length of square base and h is the height .
![A = 6^2 + \dfrac{6\times 5}{2}\\\\A = 51 \ units^2](https://tex.z-dn.net/?f=A%20%3D%206%5E2%20%2B%20%5Cdfrac%7B6%5Ctimes%205%7D%7B2%7D%5C%5C%5C%5CA%20%3D%2051%20%5C%20units%5E2)
Therefore, total area in square units is 51.