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3 years ago

Which relation is a function of x?

Mathematics

2 answers:

Monica [59]3 years ago

5 0

Answer:

Table D

Step-by-step explanation:

I just took the quiz on edge

USPshnik [31]3 years ago

3 0

Answer:

The fourth function

Step-by-step explanation:

You can never have repeating x-values. You can have repeating y-values though. Whenever determining whether something is a function, just look at whether it has repeating x-values or not. If it does, it is not a function. If it doesn't, it is a function.

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1. Find the value of x in the equation 2N x 20 15 31 X O A. 1 B. 16 OD. 25 ext Review Answer selections

Solnce55 [7]

There a absolute value so mark out the negative and 25 / by 16 is 1 so 1 is your answer if you really do the problem on paper

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3 years ago

The grocery store is located at a point on a coordinate plane with the same y-coordinate as the bank but with the opposite x-coo

Alexxandr [17]

Across the y axis. This question becomes easier if you graph it out in your head. Let's say the bank is at (2,2). Because the grocery store has an opposite x coordinate, the bank would be at (-2,2). If you look at this in your head, they are not even on different sides of the x axis, and therefore must be reflected across the y axis.

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2 years ago

Read 2 more answers

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so: