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yanalaym [24]
3 years ago
12

Divide the sum of (-24),(-10) and (-40) by the product of (-5) and 3​

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0

Hello!

Sum: the total of a set of numbers obtained using addition.

Product: the number obtained from multiplying a set of numbers.

The sum of -24, -10, and -40, is -74

the product of -5 and 3, is -15

now divide: -74 / -15 = <u>4.9333</u>

I hope this helps, and have a nice day!

PilotLPTM [1.2K]3 years ago
5 0

Answer:

4.93333...

Step-by-step explanation:

-24 + (-10) + (-40) = -74

-5 * 3 = -15

-74 /-15 = 4.93333...

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In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct
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(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

                  =(0.93\times0.03)+(0.10\times0.97)\\=0.1249

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

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3 years ago
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