<span>we will isolate that right triangle marked off with the little angle thing.
</span>We know that, in that right triangle, one of the legs measures 22 ft, and the angle (adjacent) to it, meausres 9.2 degreesIn this case, <span>tan9.2=<span>x/22</span></span><span> where x is that unkown length
</span>cross multiply.
<span>your final answer is equal to x+5.6</span>
F ` ( x ) = ( x² )` · e^(5x) + x² · ( e^(5x) )` =
= 2 x · e^(5x) + 5 e^(5x) · x² =
= x e^(5x) ( 2 + 5 x )
f `` ( x ) = ( 2 x e^(5x) + 5 x² e^(5x) ) ` =
= ( 2 x ) ˙e^(5x) + 2 x ( e^(5x) )` + ( 5 x² ) ` · e^(5x) + ( e^(5x)) ` · 5 x² =
= 2 · e^(5x) + 10 x · e^(5x) + 10 x · e^(5x) + 25 x² · e^(5x) =
= e^(5x) · ( 2 + 20 x + 25 x² )
Answer:
The average rate of change on the given interval is 9/70
Step-by-step explanation:
Here, we are to find the average rate of change of the function on the given interval
We proceed as follows;
on an interval [a,b] , we can find the average rate of change using the formula;
f(b) - f(a)/b-a
From the question;
a = 0
b = 3
f(0) = -3/5
f(3) = -3/14
Substituting the values, we have;
-3/14-(-3/5)/3-0
= 3/5-3/14/3
= (42-15)/70/3
= 27/70/3
= 27/70 * 1/3 = 9/70
Answer:
Option b is correct.
Step-by-step explanation:
From the given condition : Seven less than the quotient of a number, x, and twelve is five times the number.
Here, the number is x
The quotient of a number x and twelve is expressed as , 
Seven less than the quotient of a number, x, and twelve is expressed as, 
Five times the number mean, 
Therefore, we have an equation in the form of <em>x</em> from the given condition as:
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