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3 years ago

23.1 + 53 23.1 + 25.3 484 48.4

Mathematics

2 answers:

DiKsa [7]3 years ago

5 0

Your answer would be 76.1

seraphim [82]3 years ago

4 0

Answer:

76.1

Step-by-step explanation:

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The answer is D........

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4 years ago

Simplify: -6x+3y-2x-5y

meriva

Answer:

-8x-2y

Step-by-step explanation:

Combine Like Terms (-6x + -2x) and (-5y + 3y).

5 0

4 years ago

Read 2 more answers

Can someone give me the answers to this or how to find the answers to it?

faltersainse [42]

the discriminant formula is b^2-4ac

so plug the values from each equation into the formula and solve, the result is the value of the discriminant

if the number is negative, there are no real roots/x-int

if it is 0 there is one real root/x-intercepts

if it is positive it has 2 real roots/x-int

and to find the actual solutions you have to plug the values into the quadratic formula

6 0

4 years ago

Solve <br><br> 1/5(20−10x)−8x>−6x−16

Harrizon [31]

Answer:

Step-by-step explanation:

4 - 2x - 8x > -6x - 16

4 - 10x > -6x - 16

4 - 4x > -16

-4x > -20

x < 5

7 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

4 years ago