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Oduvanchick [21]
2 years ago
5

A bag contains 8 white, 4 red, 7 green, and 5 blue marbles. Eight marbels are withdrawn randomly. How many withdrawn marbles wer

e white if the chance of withdrawing a white marble is now 1/4?
Mathematics
1 answer:
Wewaii [24]2 years ago
7 0

We are starting with 8+4+7+5=24 marbles. We're taking out 8, so we'll be left with 24-8=16 marbles. Think about those 16. If the probability of drawing a white one is 1 in 4, that means that 1/4 of the marbles are white. 1/4 of 16 is 16/4 = 4 marbles are white. Since we started with 8 white, and there are 4 left, we must have taken out 8-4 = 4 white marbles.

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Identify the 8th term of the given geometric sequence. 1/2, 2, 8, 32,...
IrinaK [193]
<h3>Geometric sequence.</h3>

A geometric sequence goes from one term to the next by always multiplying or dividing by the constant value except 0. The constant number multiplied (or divided) at each stage of a geometric sequence is called the common ratio (r).

We have:

a_1=\dfrac{1}{2}\\\\a_2=2\\\\a_3=8\\\\a_4=32\\\vdots

Find the common ratio:

\boxed{r=\dfrac{a_n}{a_{n-1}}}\Rightarrow r=\dfrac{2}{\frac{1}{2}}=\dfrac{8}{2}=\dfrac{32}{8}=...\\\\\boxed{r=4}

<h3>The formula of the n-th term of a geometric sequence:</h3>

\boxed{a_n=a_1\cdot r^{n-1}}

Substitute:

a_1=\dfrac{1}{2},\ r=4,\ n=8\\\\a_8=\dfrac{1}{2}\cdot4^{8-1}=\dfrac{1}{2}\cdot4^7=\dfrac{1}{2}\cdot16384\\\\\huge\boxed{a_8=8192}

<h3>Method step by step:</h3>

a_4=32,\ r=4\\\\a_5=a_4\cdot r\Rightarrow a_5=32\cdot4=128\\\\a_6=a_5\cdot r\Rightarrow a_6=128\cdot4=512\\\\a_7=a_6\cdot r\Rightarrow a_7=512\cdot4=2048\\\\a_8=a_7\cdot r\Rightarrow a_8=2048\cdot4=8192

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2 years ago
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