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alex41 [277]
3 years ago
10

V(x + 9)2 = + 25 If x + 9 = 5, then x = If x + 9 = -5, then x =

Mathematics
1 answer:
ipn [44]3 years ago
4 0

Answer:

x = -4, v = 2.5

x = -14, v = -2.5

Step-by-step explanation:

I am a bit confused with the beginning part of the question. From what I understand, you are trying to solve for x and then plug x into the top equation to find the value for V. I am sorry if that is not what you are looking for. If it is, look below!

x + 9 = 5

x = 5 -9

x = -4

v(x + 9)2 = 25

v(-4 + 9)2 = 25

v(5)2 = 25

v(10) = 25

v = 25/10

v = 2.5

x + 9 = -5

x = -5 -9

x = -14

v(x + 9)2 = 25

v(-14 + 9)2 = 25

v(-5)2 = 25

v(-10) = 25

v = 25/(-10)

v = -2.5

I hope this helped! If not, I am sorry. :(

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Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

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2 years ago
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Answer:

Step-by-step explanation:

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Answer:
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Explanation:
Assume the number of phone calls that Stephanie made is x.
We are given that:
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