All categories

3 years ago

I NEED HELP, THIS IS DUE BY TONIGHT

Mathematics

1 answer:

finlep [7]3 years ago

4 0

Well the minutes are 198 still working on the rest

You might be interested in

What is the solution of log3x + 4125 = 3?

Advocard [28]

Log3 (x) + 4125=3 final answer

8 0

3 years ago

Read 2 more answers

Find the value of x and the value of y

WARRIOR [948]

I’m pretty sure it’s b.

6 0

2 years ago

Which relations are functions?

guapka [62]

Answer:

The 1st and 2nd graph are functions while the 3rd and 4th aren't.

Step-by-step explanation:

The first and second graph doesn't have more than one output for each input. The third and fourth graph isn't a function since there's more than one output for the same input given. If you do the vertical line test, then you'll know which one is a function and which one is not a function. Hope this helps :)

3 0

2 years ago

Write the percent as a mixed number in simplest form.<br> 168%

vladimir2022 [97]

Answer:

1 and 17/25

Step-by-step explanation:

First, you make it into a fraction. So because percents are out of 100, it would be 168/100. Then, you take 100 out of it to get a mixed number, 1 and 68/100, and then simplify 68/100 by dividing both sides by the greatest common factor, which is 4. 68/100÷4=17/25. The answer would be 1 and 17/25.

(hope this helps :P)

4 0

2 years ago

Example 2: Combining Use of the Multiplication and Addition Rules

bulgar [2K]

Answer:

The probability of getting 6's on both cubes is $\frac{1}{36}$ .

The probability that the total score is at least 11 is $\frac{1}{12}$ .

Step-by-step explanation:

Consider the provided information.

A red cube has faces labeled 1 through 6, and a blue cube has faces labeled in the same way.

Part (A) Both cubes show 6’s.

Probability of getting 6 on red cube is $\frac{1}{6}$

Probability of getting 6 on blue cube is $\frac{1}{6}$

Thus, the probability of getting 6's on both cubes is:

$P(\text{Both 6's})=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}$

Hence, the probability of getting 6's on both cubes is $\frac{1}{36}$ .

Part (B) The total score is at least 11.

The possible number of outcomes in which total score is at least 11 is:

Red shows 6 and Blue shows 5.

Blue shows 6 and Red shows 5.

Blue shows 6 and Red shows 6.

Thus, the probability of total score is at least 11.

$P(\text{Total is at least 11})=\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}\\P(\text{Total is at least 11})=\frac{1}{12}$

Hence, the probability that the total score is at least 11 is $\frac{1}{12}$ .

3 0

2 years ago