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natima [27]
4 years ago
13

I NEED HELP, THIS IS DUE BY TONIGHT

Mathematics
1 answer:
finlep [7]4 years ago
4 0
Well the minutes are 198 still working on the rest
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The endpoints of GH are G(10,1) and H(3,5). What is the midpoint of GH?
svet-max [94.6K]

Answer:

The answer is (6.5,3)

Step-by-step explanation:

The solution is in the image

8 0
2 years ago
S = { x ; x is a multiple of 8. 0 < x <30 } Describe this set in another method​
Firdavs [7]

Step-by-step explanation:

<em>Hi</em><em>,</em>

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<em>S</em><em>=</em><em> </em><em>{</em><em>8</em><em>,</em><em>1</em><em>6</em><em>,</em><em>2</em><em>4</em><em>}</em><em>.</em>

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3 0
3 years ago
Find the approximate area of the shaded region below, consisting of a right triangle with a circle cut out of it.
Kazeer [188]

Answer:

π×10^2=314.15

Step-by-step explanation:

hope it helps

7 0
3 years ago
a small table is 2 feet by 3 feet a large table is twice as long and rwice as wide as the small table. Whats the area of the lar
Scorpion4ik [409]

Answer:

The area of larger table is 24 square feet.

Step-by-step explanation:

Given are the length and width of small table

l_s = 2\ ft\\w_s = 3\ ft

The area of a rectangular table is calculated by multiplying the length and width. It is also given that the length and width of the larger table is double the length and width of small table

So the length and width of larger table will be:

l_l = 2*2 = 4\ feet\\w_l = 3*2 = 6\ feet

The area of larger table will be:

A_l = l_l*w_l\\= 4 * 6\\=24\ ft^2

Hence,

The area of larger table is 24 square feet.

7 0
3 years ago
A study was done to determine the average number of homes that a homeowner owns in his or her lifetime. For the 60 homeowners su
const2013 [10]

Answer:

D) (3.67, 4.73)

Step-by-step explanation:

Confidence Interval for the true average number of homes that a person owns in his or her lifetimecan be calculated using M±ME where

  • M is the average number of home owned (4.2)
  • ME is the margin of error from the mean

And margin of error (ME) can be calculated as

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic in the given confidence level(1.96)
  • s is the standard deviation of the sample(2.1)
  • N is the sample size (60)

Putting the numbers we get ME=\frac{1.96*2.1}{\sqrt{60} }≈0.53

Then the 95% confidence interval is 4.2±0.53 or (3.67, 4.73)

6 0
3 years ago
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