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3 years ago

What is correct answer to -5-(-8)=

Mathematics

2 answers:

tino4ka555 [31]3 years ago

8 0

Answer:

Step-by-step explanation:

Cerrena [4.2K]3 years ago

7 0

Answer:

$3$

Step-by-step explanation:

To solve this, we first use the rule:

$- ( - x) = x$

as two negatives equal a positive.

Hence

$- 5 - ( - 8) = - 5 + 8$

which you get an answer of

$3$

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2 years ago

If x is 12% of 180, then what is the value of 7x ?

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3 years ago

Eli wanted to order candy online. Company A is offering 2 1/2 pounds of chocolate for $32.00. How much is Company A charging per

Komok [63]

Answer:

Therefore, Company B is offering the lowest price/lb at $12.73/lb.

So, Company A's price / lb = ($32.50/2.5lbs) = $13.00/lb

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To determine price per lb, divide dollar amount by lbs.

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3 years ago

For a certain commodity the supply equation is given by S = 2p + 5 At a price of $1, there is a demand for 19 units of the commo

slava [35]

Answer:

The demand equation is: D=-4p+23

Step-by-step explanation:

To get started, we should keep in mind that the market price (p=3) occurs when supply equals demand ,therefore when p=3

S=2(3)+5=11

Thus, when p=3 D=11 and, according to the problem when p=1 D=19.

We already know two points on the demand curve. Great!

The demand equation is linear, so it has form D=bp+c.

The variable b is the slope of the demand linear equation . It can be computed through the formula

$b=\frac{y2-y1}{x2-x1}$ . equation 1

Substituting the two points (3,11) and (1,19) on equation 1.

$b=\frac{19-11}{1-3} =\frac{8}{-2}$

b=-4

Now we can find the value of intercept of the demand equation c trough point-slope form y-y1=b(x-x1).

We can use any of the points. Let's take (3,11) and write in point-slope :

y-11=-4(x-3)

y=-4x+11+12

y=-4x+23

Rewrite the linear equation according our variables D and p

D=-4P+23

Finally we found the demand equation !

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3 years ago

Prove that root 7 is irrational by the method of contradiction

Alchen [17]

Let assume that $\sqrt7$ is a rational number. Therefore it can be expressed as a fraction $\dfrac{a}{b}$ where $a,b\in\mathbb{Z}$ and $\text{gcd}(a,b)=1$ .

$\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2$

This means that $a^2$ is divisible by 7, and therefore also $a$ is divisible by 7.

So, $a=7k$ where $k\in\mathbb{Z}$

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Therefore $\sqrt7$ is an irrational number.

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3 years ago