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Maru [420]
3 years ago
15

The reaction between nitrogen and hydrogen to produce ammonia is described by the equilibrium reaction 3 H 2 + N 2 − ⇀ ↽ − 2 NH

3 What substances are present in the reaction mixture when equilibrium has been obtained? NH + 4 NH 3 H 2 N 2
Chemistry
1 answer:
77julia77 [94]3 years ago
8 0

The question correctly reads:

The reaction between nitrogen and hydrogen to produce ammonia is described as an equilibrium reaction. What substances are present in the reaction mixture when equilibrium has been obtained?

3H2 + N2 = 2NH3

N2

H2

NH4+

NH3

Answer:

N2,H2,NH3

Explanation:

Equilibrium is said to be attained when the rate of forward reaction equals the rate of reverse reaction. That is forward and reverse reactions occur at the same rate. The rate at which reactants are reformed, is the same rate at which products are formed. Hence at equilibrium both reactants and products are present in the reaction mixture. This implies that nitrogen, hydrogen and ammonia are all present in the reaction mixture at equilibrium.

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First option (Independent State)

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3 years ago
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What is the Lewis dot structure for the formula ch3br?
Alenkasestr [34]

You may find the Lewis dot structure of the CH₃-Br in the attached picture.

Explanation:

In the Lewis dot structure we represent the unpaired electrons using dots.

Bromide have one electron shared with one electron from the carbon to form a covalent bond, while the remaining electrons remains unpaired. We represent the six unpaired electrons of the bromide with dots.

Learn more about:

structure of organic compounds

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6 0
3 years ago
A solid yellow stripe is to be painted in the middle of a certain highway. If 1 gallon of paint covers an area of p square feet
Zolol [24]

Answer:

440mt/p gallons

Explanation:

We are told that one gallon of paint covers an area of p square feet. Knowing this then, the question becomes how much paint is needed to cover a stripe that is t inches wide and m miles long.

Let us first use the dimensions of the stripe to find how much area that is in square feet. A stripe is rectangular so we will calculate the area as follows:

Area of stripe = width x length

                       = t inches x m miles              (we need to convert both to feet)

                       = (t inches x 1 ft/12 inches) x (m miles x 5280 ft/1 mi)

                       =440mt square feet

ow we can find out how much paint will be needed by using ratios

p square feet : 1 gallon

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6 0
3 years ago
Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
just olya [345]
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.

In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.

On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive. 


7 0
4 years ago
a sample of unknown material weighs 500 n in air and 200 n when immesersed in alcholol with a specfic gravity of 0.7 what is the
svet-max [94.6K]

Answer: The mass density is 1166.36 kg/m^{3}.

Explanation:

Given: Weight of sample in air (F_{air}) = 500 N

Weight of sample in alcohol (F_{alc}) = 200 N

Specific gravity = 0.7 = 0.7 \times 1000 = 700 kg/m^{3}

Formula used to calculate Buoyant force is as follows.

F_{B} = F_{air} - F_{alc}\\= 500 - 200 \\= 300 N

Hence, volume of the material is calculated as follows.

V = \frac{F_{B}}{\rho \times g}

where,

F_{B} = Buoyant force

\rho = specific gravity

g = acceleration due to gravity = 9.81

Substitute the values into above formula.

V = \frac{F_{B}}{\rho \times g}\\= \frac{300}{700 \times 9.81}\\= \frac{300}{6867}\\= 0.0437 m^{3}

Now, mass of the material is calculated as follows.

mass = \frac{F_{air}}{g}\\= \frac{500 N}{9.81}\\= 50.97 kg

Therefore, density of the material or mass density is as follows.

Density = \frac{mass}{volume}\\= \frac{50.97 kg}{0.0437 m^{3}}\\= 1166.36 kg/m^{3}

Thus, we can conclude that the mass density is 1166.36 kg/m^{3}.

7 0
3 years ago
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