You may find the Lewis dot structure of the CH₃-Br in the attached picture.
Explanation:
In the Lewis dot structure we represent the unpaired electrons using dots.
Bromide have one electron shared with one electron from the carbon to form a covalent bond, while the remaining electrons remains unpaired. We represent the six unpaired electrons of the bromide with dots.
Learn more about:
structure of organic compounds
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Answer:
440mt/p gallons
Explanation:
We are told that one gallon of paint covers an area of p square feet. Knowing this then, the question becomes how much paint is needed to cover a stripe that is t inches wide and m miles long.
Let us first use the dimensions of the stripe to find how much area that is in square feet. A stripe is rectangular so we will calculate the area as follows:
Area of stripe = width x length
= t inches x m miles (we need to convert both to feet)
= (t inches x 1 ft/12 inches) x (m miles x 5280 ft/1 mi)
=440mt square feet
ow we can find out how much paint will be needed by using ratios
p square feet : 1 gallon
440mt square feet : x
x = 440mt/p gallons
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case,
reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is
least reactive.
On other hand,
reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is
most reactive.
Answer: The mass density is 1166.36
.
Explanation:
Given: Weight of sample in air
= 500 N
Weight of sample in alcohol
= 200 N
Specific gravity = 0.7 = 
Formula used to calculate Buoyant force is as follows.

Hence, volume of the material is calculated as follows.

where,
= Buoyant force
= specific gravity
g = acceleration due to gravity = 9.81
Substitute the values into above formula.

Now, mass of the material is calculated as follows.

Therefore, density of the material or mass density is as follows.

Thus, we can conclude that the mass density is 1166.36
.