Answer:
The mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.351 %.
Explanation:
Given,
Mass of Sucrose = 7.6 grams
Mass of Water = 83.4 grams
In this solution, Sucrose is solute and water is the solvent.
Mass percent of a solution can be calculated using the formula,
Mass percent = (Mass of Solute/Mass of Solution)(100)
As sucrose is solute, mass of solute = 7.6 grams
As the solution contains both Sucrose and Water,
Mass of solution = 7.6 grams + 83.4 grams = 91 grams
Substituting the values, Mass percent = (7.6/91)(100) = 8.351 %.
# of atoms per mol = Avogadro’s # (6.022 x 10^23)
Number of mols = mass of substance / molar mass
73 g / 40.08 g = 1.8 mols of Ca in 73 grams
1.8 mols x avagadro’s # = 1.1 x 10^24 atoms in 73 grams of Ca
Answer:
Explanation:
Such types of compounds in which conjugated planer ring system and delocalized pi electrons are present are called aromatic compounds such as Toluene, Benzene and some other. Generally, these compounds follow Huckle's rule. The trisubstituted ring means a compound in which three hydrogen atoms are replaced by three other groups. In the given compound two hydrogen atoms are replaced by two methyl groups and one hydrogen atom is replaced by one Chlorine atom. From the given compound , and can be drawn.
Answer:
Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol
Option C is correct
Explanation:
Step 1: Data give
Mass of Ne = 2.0 grams
Molar mass of neon = 20.18 g/mol
Number of Avogadro = 6.0 *10^23 /mol
Step 2: Calculate number of moles of neon
Moles Ne = Mass of ne / Molar mass of ne
Moles Ne = 2.0 / 20.18 g/mol
Moles Ne = 0.099 moles
Step 3: Calculate nulber of particles
Number of particles = 6.022*10^23 / mol * 0.099 moles = 5.96 *10^22
Number of particles = 6.022*10^23 * (2.0g/ 20.18g/mol)
Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol
Option C is correct
