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2 years ago

Methanol burns in oxygen to form carbon dioxide and water. find delta h

1 answer:

6 0

Answer is: enthalpy is -1276,8 kJ.
Chemical reaction: 2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂<span>O(g).
</span>ΔH(CH₃OH) = -238,7 kJ/mol.
ΔH(H₂O) = -241,8 kJ/mol.
ΔH(CO₂) = -<span>393,5 kJ/mol.
</span>ΔH(O₂) = 0 kJ/mol.
ΔHreaction = ∑ΔHproducts - ∑ΔHreactants
ΔHreaction = (2·(-393,5) + 4·(-241,8) - (2·(-238,7))
ΔH = (-787 - 967,2) + 477,4
ΔH = -1276,8 kJ.

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Use the pictures below to answer the following question what type of bond is this

mezya [45]

I literally hate chem but I think it’s ionic, I’m not not completely sure but it kinda sounds about right . Not the best anwser haha hope it kinda helps lol

4 0

2 years ago

Calculate the molality of a solution formed by adding 6.30 g NH4CL to 15.7 g of water

babymother [125]

Answer:

Molality = 7.5 mol/kg

Explanation:

Given data:

Mass of NH₄Cl = 6.30 g

Mass of water = 15.7 g (15.7/1000 =0.016 kg)

Molality = ?

Solution:

Formula of molality:

Molality = Moles of solute / mass of solvent in gram

Now we will first calculate the number of moles of solute( NH₄Cl )

Number of moles = mass/ molar mass

Molar mass of NH₄Cl = 53.491 g/mol

Number of moles = 6.30 g/ 53.491 g/mol

Number of moles = 0.12 mol

Now we will calculate the molality.

Molality = Moles of solute / mass of solvent in gram

Molality = 0.12 mol / 0.016 kg

Molality = 7.5 m

or (m=mol/kg)

Molality = 7.5 mol/kg

6 0

2 years ago

Liters of a 2.40 M

kotykmax [81]

Answer:

1.42 L

Explanation:

Step 1:

The following data were obtained from the question :

Molarity of KBr = 2.40 M

Mole of KBr = 3.40 moles

Volume of solution =?

Step 2:

Determination of the volume of the solution.

Molarity of solution is simply the mole of the solute per unit volume the of solution. It is given as :

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 3.4/2.4

Volume = 1.42 L

Therefore, the volume of the solution is 1.42 L

6 0

2 years ago

Calculate the mass in grams for each of the following liquids.

WITCHER [35]

The density is calculated as mass per volume, so if we want to solve for mass, we would multiply density by volume.
For Part A: if we have a density of 0.69 g/mL, and a volume of 280 mL, multiplying these will give a mass of: (0.69 g/mL)(280 mL) = 193.2 g. Rounded to 2 significant figures, this is 190 g gasoline.
For Part B: if we have a density of 0.79 g/mL, and a volume of 190 mL, multiplying these will give a mass of: (0.79 g/mL)(190 mL) = 150.1 g. Rounded to 2 significant figures, this is equal to 150 g ethanol.

3 0

2 years ago

Look up the active ingredient in baking soda. Write a molecular and net ionic equation when that active ingredient is mixed with

Volgvan

Answer:

The active ingredients in baking soda (NaHCO3) are

$Na^+$ and $HCO3^-$