Answer:
Follows are the solution to this question:
Step-by-step explanation:
Technician selects three out of 5 systems
In C(5,3)=10ways, this can be achieved
In part a:
Space sample chooses 3 of a 5 systems
In point b:
A =MODULE WHICH INCLUDE M1 minimal amount of effort
Outcomes probable =
In point c:
B = highest effort that is 
Potential result=
In point d:
In point e:
In point f:
In point g:
In point h:
Answer:
Arc DB = 146
x = 5
Step-by-step explanation:
Remark
The relationship between the large arc, the small arc and the intersecting angle is
1/2 (large arc - small arc) = intersecting angle.
Givens
Large arc = 25x + 21
Small arc = 96
5x
Solution
1/2*(25x + 21 - 96) = 5x*2 Multiply both sides by 2
25x + 21 - 96 = 10 x Combine
25x - 75 = 10x Subtract 25x from both sides
-75 = 10x - 25x
-15x = -75
x = 5
DB = 25x + 21
DB = 25*5 + 21
DB = 125 + 21
DB = 146
Tell me if this is not in the choices.
X = sqrt(5^2 - 3^2) = 4
y = sqrt(7^2 - 3^2) = sqrt 40
Horizontal distance = x + y + 3 = 7 + sqrt40
Answer:
0.545455
Step-by-step explanation:
Answer: ∠B=70°
Step-by-step explanation:
It is shown in the diagram that ∠A and ∠B is vertical angles.
- Vertical angle theorem: opposite angles are congruent.
<u>Solve:</u>
∠A=∠B
8x+6=4x+38
4x=32
x=8
<h2>∠B=4x+38=4(8)+38=32+38=70°</h2>
