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3 years ago

Iron has a density of 7.86 g/cm3. Calculate the volume (in dL) of a piece of iron having a mass of 3.11 kg

Chemistry

1 answer:

SpyIntel [72]3 years ago

5 0

Answer:

The volume is 3.96 dL

Explanation:

<u>Step 1: Convert ml to dl</u>

1Liter = 1000ml = 10³ ml

1Liter = 10 dl

⇒ 1 Liter has 1000ml or 10 dl

⇒ The ratio can be written as : 10dl/ 1000ml = 1 dl / 100ml

<u>Step 2: Convert cm³ </u>=

⇒ 1cm³ is equal to 1 ml.

<u>Step 3: Calculate volume</u>

⇒ We use the formule of density here, which is : Density (p) = mass (g) / volume( cm³)

⇒ 7.86 g/ cm³ = 3110 grams / Volume ( cm³)

⇒Volume = 3110 grams / 7.86g/cm³ = 395.67 cm³

395.67 cm³ = 395.67 ml = 0.39567 L = 3.96 dL

3.96 dL is reported to three significant digits due to the precision reported for the density.

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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the

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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

$\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}$

$P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}$

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

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