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Novay_Z [31]
4 years ago
10

What are the zeros and x-intercepts of this quadratic function?

Mathematics
1 answer:
jek_recluse [69]4 years ago
8 0

i think its D and A I THINK.

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Which set of ordered pairs is a function
svet-max [94.6K]

Answer:

(1, 1), (2, 2), (3, 3)

Step-by-step explanation:

it is increasing at a constant rate.

8 0
3 years ago
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Someone help me pls!!!!!!!!<br> math problem
Liono4ka [1.6K]

Answer:

{1,6}

Step-by-step explanation:

the second box is always where the y values/range are

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3 years ago
An=−2+32(n−1)<br><br> What is the 21st term of the sequence?
OLEGan [10]

Answer:

a₂₁ = 638

Step-by-step explanation:

substitute n = 21 into the explicit formula

a₂₁ = - 2 + 32(21 - 1) = - 2 + 32(20) = - 2 + 640 = 638

5 0
2 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
4 years ago
Pls help me help me​
grandymaker [24]

Answer:

C.

Step-by-step explanation:

When two lines are parallel, their slopes are the same.

Since the slope of line <em>l </em>is 2/7, the slope of its parallel line <em>m</em> must also be 2/7.

The answer is C.

3 0
3 years ago
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