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max2010maxim [7]
3 years ago
10

Is the relationship between red and blue marbles additive or multiplicative? Write the

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0
D I just took the test
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Write and solve a word problem that can be modeled by addition of two negative integers?
andrezito [222]
John owes 15 dollars to Bill, then another 2 dollars to Joey. How much money does John have?

Since John has 0 dollars to give, he has (-15)+(-2) =-17 dollars (as 15+2=17, so the same can be applied negatively) as the first 17 dollars he gets has to be given to Bill and Joey
3 0
3 years ago
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Calculus hw, need help asap with steps.
nikdorinn [45]

Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let f(n) = \frac{(-1)^{n+1}}{n!}

The summation given to us represents the following

\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum S_1 is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say S_1 = f(1) = 1

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like S_3 = S_2 + f(3) and S_4 = S_3 + f(4)

In general, S_{n+1} = S_{n} + f(n+1) so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find S_5

S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333

The scratch work for f(5) is shown below.

7 0
2 years ago
Suppose you inherited a house that was purchased in 1950 for 20,000. It is now 2015 and the value of the house has increased by
Masja [62]

Answer:

I think the house would now costs $85,000

Step-by-step explanation:

First, I multiplied by how many years between 1950 to 2015 and 5 to get 325.

Next, I divided 20,000 by 100 to get 200 to find 1% of 20,000.

Then, I multiplied 325 by 200 to get 65,000

Finally, I added 20,000 to 65,000 to get 85,000

So, I guess/answer is $85,000

If I was wrong, then just say, "Sorry, but that was incorrect."

5 0
3 years ago
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Question is in the image
Rudik [331]
The unit rate that the turtle is crawling is: (1/23)/(5/6) = (1/23)*(6/5) = 6/115 miles/hour.
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antiseptic1488 [7]
The answer to your question is .........
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