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BaLLatris [955]
3 years ago
6

If y varies inversely as x, and y = 10 as x = 7, find y for the x-value of 10.

Mathematics
1 answer:
Finger [1]3 years ago
3 0
I have the same question... Anyone know the answer?
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Ab + c = d solve for a
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a=d-c/b

Subtract c from both sides

a=d-c/b

divide both sides by b

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13+(3+7)=(13+3)+7 what property is that​
Reil [10]

Answer: Associative property

Step-by-step explanation:

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Part 2: Create a scenario for a geometric sequence. For example, Anthony goes to the gym for ______ minutes on Monday. Every day
Ugo [173]
An example scenario is:

Anthony goes to the gym for <em>20</em> minutes on Monday. Every day he <em>multiplies</em> his gym time by <em>2</em>. 

On the fifth day, he will spend spend 320 minutes in the gym. 

The formula used to determine the 5th term is,

                                       a5 = 20 x 2^(r -1) 

where r is the common ratio equal to 2. 


5 0
3 years ago
How to do arrays in repeated halving
Arlecino [84]

Answer:

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5 0
2 years ago
This is for algebra 2 can someone tell me if I’m right and can someone explain how do you get a= ?
algol13

Answers:

a = 2

h = 3

k = -3

You have the correct h and k values. Nice work so far.

==========================================================

Explanation:

(h,k) is the vertex. So (h,k) = (3,-3) meaning h = 3 and k = -3

To get the value of 'a', we need to plug in some point on the red graph. Each point is of the form (x,y). We can pick any point we want that isn't the vertex.

Let's pick (0,3) which is the y intercept. I'm picking this because 0 is an easy number to work with

------------

y = a|x-h| + k

y = a|x-3| + (-3) .... plug in the h,k values

y = a|x-3| - 3

3 = a|0-3| - 3 .... plug in (x,y) = (0,3)

3 = a|-3| - 3

3 = a*3 - 3

3 = 3a - 3

3a-3 = 3

3a = 3+3 ... adding 3 to both sides

3a = 6

a = 6/3 ... divide both sides by 3

a = 2

The value a = 2 indicates that the parent function y = |x| has been stretched vertically by a factor of 2. So it is twice as tall as before. Then it has been shifted to place the vertex at (3,-3) as shown in the graph.

------------

You may be wondering why you can't pick on the vertex for (x,y)

Let's see what happens if we use (x,y) = (3,-3)

y = a|x-3| - 3

-3 = a|3-3| - 3 ... plug in (x,y) = (3,-3)

-3 = a|0| - 3 ... uh oh, we get 0 here

-3 = a*0 - 3

-3 = 0 - 3

-3 = -3

We get a true statement, which is nice, but it doesn't tell us anything about what the value of 'a' is. That 'a' term goes away entirely. So I avoided using x = 3 to prevent x-3 from being 0.

4 0
3 years ago
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