Answer:
while all of the world can experience a solar eclipse it is not normally at the same time so one part of the earth might have it but not the other and even in one area if there is one in north america like the last one in texas we did not have a full eclipse
Answer:a substance with low ability or no ability to conduct energy
Explanation:
Answer:
The bikers speed at the top of other hill is <u>25.82 m/s.</u>
Explanation:
Considering the biker is riding on a frictionless surface.
∴ There is no non-conservative or external force acting on the biker.
Hence we can conserve the energy of biker and bike as a system.
Let,
= 44m
= 10m
Since the biker starts from rest , his initial speed
= 0 m/s
Let final speed of the bike at the top of other hill be
.
∴ Initial Energy (at the top of 44m hill) = ![mgh_{1}](https://tex.z-dn.net/?f=mgh_%7B1%7D)
Final Energy (at the top of 10m hill) =
.
Conserving both the energies , we get
= ![mgh_{2} + \frac{1}{2}mv_{2} ^{2}](https://tex.z-dn.net/?f=mgh_%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7Dmv_%7B2%7D%20%5E%7B2%7D)
∴ ![v_{2} = \sqrt{2g(h_{1}-h_{2} )}](https://tex.z-dn.net/?f=v_%7B2%7D%20%3D%20%5Csqrt%7B2g%28h_%7B1%7D-h_%7B2%7D%20%29%7D)
Substituting the values for g ,
,
, we get
= 25.82 m/s
Answer:
the mass of the body is 0.02 kg.
Explanation:
Given;
relative density of the oil,
= 0.875
mass of the object in oil,
= 0.013 kg
mass of the object in water,
= 0.012 kg
let the mass of the object in air = ![M_a](https://tex.z-dn.net/?f=M_a)
weight of the oil, ![W_0 = M_a - 0.013](https://tex.z-dn.net/?f=W_0%20%3D%20M_a%20-%200.013)
weight of the water, ![W_w = M_a - 0.012](https://tex.z-dn.net/?f=W_w%20%3D%20M_a%20-%200.012)
The relative density of the oil is given as;
![\gamma_0 = \frac{density \ of \ oil }{density \ of \ water} = \frac{W_0}{W_w} = \frac{M_a -0.013}{M_a -0.012} \\\\0.875 = \frac{M_a -0.013}{M_a -0.012}\\\\0.875(M_a - 0.012) = M_a - 0.013\\\\0.875M_a - 0.0105 = M_a -0.013\\\\0.875M_a - M_a = 0.0105 - 0.013\\\\-0.125 M_a = -0.0025\\\\M_a = \frac{0.0025}{0.125} \\\\M_a = 0.02 \ kg](https://tex.z-dn.net/?f=%5Cgamma_0%20%3D%20%5Cfrac%7Bdensity%20%5C%20of%20%5C%20oil%20%7D%7Bdensity%20%5C%20of%20%5C%20water%7D%20%3D%20%5Cfrac%7BW_0%7D%7BW_w%7D%20%3D%20%5Cfrac%7BM_a%20-0.013%7D%7BM_a%20-0.012%7D%20%5C%5C%5C%5C0.875%20%3D%20%5Cfrac%7BM_a%20-0.013%7D%7BM_a%20-0.012%7D%5C%5C%5C%5C0.875%28M_a%20-%200.012%29%20%3D%20M_a%20-%200.013%5C%5C%5C%5C0.875M_a%20-%200.0105%20%3D%20M_a%20-0.013%5C%5C%5C%5C0.875M_a%20-%20M_a%20%3D%200.0105%20-%200.013%5C%5C%5C%5C-0.125%20M_a%20%3D%20-0.0025%5C%5C%5C%5CM_a%20%3D%20%5Cfrac%7B0.0025%7D%7B0.125%7D%20%5C%5C%5C%5CM_a%20%3D%200.02%20%5C%20kg)
Therefore, the mass of the body is 0.02 kg.
Given resistance in ohms and current in ampere, the power can be calculated by the equation,
P = I² x R
where I is current, P is power, and R is resistance
Substituting the given values,
1.00 x 10² = (I²) x 136 ohms ; I = 0.8575 amp
Then, by Ohm's law, the value of V = I x R. Substituting,
V = (0.8575 amp) x (136 ohms) = 116.619 volts
Thus, the potential difference across the lamp is approximately equal to 116.619 volts.