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vovangra [49]
2 years ago
6

Help plzDoes everyone in the earth experience solar eclipse?​

Physics
2 answers:
kaheart [24]2 years ago
4 0

Answer:

while all of the world can experience a solar eclipse it is not normally at the same time so one part of the earth might have it but not the other and even in one area if there is one in north america like the last one in texas we did not have a full eclipse

neonofarm [45]2 years ago
4 0

Answer: To answer your question.Not at all because the shadow that the moon cast on the earth is not very broad,as the earth rotates ,the path of the total eclipse is a narrow one.

Total solar eclipses are rare events actually. Although they occur somewhere on Earth every 18 months on average, this is estimated to recur at any given place only once every 360 to 410 years, on average as the case may be .

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18°C = _____ <br> A -255 K<br> B- 0 K<br> C- 18 K<br> D- 291 K
mariarad [96]

Answer:

291 K is the answer

Explanation:

to get Kelvin from Celsius use the following

Kelvin = Celsius +273

= 18 +273

= 291

7 0
2 years ago
13. What's most intriguing about Titan's atmosphere?
sineoko [7]

Answer: There is an unsolved mystery surrounding Titan's atmosphere: Because methane is broken down by sunlight, scientists believe there is another source that replenishes what is lost. One potential source of methane is volcanic activity, but this has yet to be confirmed.

Explanation:

7 0
3 years ago
What is the acceleration of a softball if it hits the ground with a force 0.50 kg and hits the catchers glove with a force of 25
Rom4ik [11]

Acceleration of the ball is 50 m/s^2

Explanation:

The acceleration of the ball can be found by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the net force

m is the mass

a is the acceleration

For the ball in this problem, we have

m = 0.50 kg (mass)

F = 25 N (force)

thereofre, the acceleration of the ball is

a=\frac{F}{m}=\frac{25}{0.50}=50 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0
2 years ago
Maggie walks to a friends house which is exactly 1500 meters due South. It takes Maggie 45 minutes for the walk and Maggie has t
Sindrei [870]

Answer:

<em>Explanation below</em>

Explanation:

<u>Speed vs Velocity </u>

These are two similar physical concepts. They only differ in the fact that the velocity is vectorial, i.e. having magnitude and direction, and the speed is scalar, just the magnitude regardless of the direction. They are strongly related to the concepts of displacement and distance, which are the vectorial and scalar versions of the space traveled by a moving object. The velocity can be computed as

\displaystyle \vec v=\frac{\vec r}{t}

Where \vec r is the position vector and t is the time. The speed is

\displaystyle v=\frac{d}{t}

To compute \vec r, we only need to know the initial and final positions and subtract them. To compute d, we need to add all the distances traveled by the object, regardless of their directions.

Maggie walks to a friend's house, located 1500 meters from her place. The initial position is 0 and the final position is 1500 m. The displacement is

\vec r=1500\ m \text{ to the south}

and the velocity is

\displaystyle \vec v=\frac{1500}{45}=33.33\ m/s\text{ to the south}

Now, we know Maggie had to make three different turns of direction to finally get there. This means her distance is more than 1500 m. Let's say she walked 500 m in all the turns, then the distance is

d=1500+500=2000\ m

If she took the same time to reach her destiny, she would have to run faster, because her average speed is

\displaystyle v=\frac{2000}{45}=44.44\ m/s

5 0
3 years ago
What is the value of acceleration due to gravity at the pole, equator and the centre of the earth
fgiga [73]

Answer:

In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.

7 0
2 years ago
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