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3 years ago

6

Help plzDoes everyone in the earth experience solar eclipse?

2 answers:

kaheart [24]3 years ago

4 0

Answer:

while all of the world can experience a solar eclipse it is not normally at the same time so one part of the earth might have it but not the other and even in one area if there is one in north america like the last one in texas we did not have a full eclipse

neonofarm [45]3 years ago

4 0

Answer: To answer your question.Not at all because the shadow that the moon cast on the earth is not very broad,as the earth rotates ,the path of the total eclipse is a narrow one.

Total solar eclipses are rare events actually. Although they occur somewhere on Earth every 18 months on average, this is estimated to recur at any given place only once every 360 to 410 years, on average as the case may be .

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The value of relative humidity becomes 100% leading to condensation of water vapor in the air into water droplets or water (dew)

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3 years ago

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Power = work/time

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4) The object that changes its position relative to a fixed point with time is called ..<br>

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3 years ago

Vector A has a magnitude of 50 units and points in the positive x direction. A second vector, B , has a magnitude of 120 units a

Alex Ar [27]

A) Vector A

The x-component of a vector can be found by using the formula

$v_x = v cos \theta$

where

v is the magnitude of the vector

$\theta$ is the angle between the x-axis and the direction of the vector

- Vector A has a magnitude of 50 units along the positive x-direction, so $\theta_A = 0^{\circ}$ . So its x-component is

$A_x = A cos \theta_A = (50) cos 0^{\circ}=50$

- Vector B has a magnitude of 120 units and the direction is $\theta_B = -70^{\circ}$ (negative since it is below the x-axis), so the x-component is

$B_x = B cos \theta_B = (120) cos (-70^{\circ})=41$

So, vector A has the greater x component.

B) Vector B

Instead, the y-component of a vector can be found by using the formula

$v_y = v sin \theta$

Here we have

- Vector B has a magnitude of 50 units along the positive x-direction, so $\theta_A = 0^{\circ}$ . So its y-component is

$A_y = A sin \theta_A = (50) sin 0^{\circ}=0$

- Vector B has a magnitude of 120 units and the direction is $\theta_B = -70^{\circ}$ , so the y-component is

$B_y = B sin \theta_B = (120) sin (-70^{\circ})=-112.7$

where the negative sign means the direction is along negative y:

So, vector B has the greater y component.

8 0

3 years ago

You send a beam of light from a material with index of refraction 1.21 into an unknown material. In order to help identify this

White raven [17]

Answer:

refractive index of the unknown material is 1.33.

Explanation:

μ₁ = 1.21

incidence angle (i) = 41.9°

refraction angle (r) = 37.3°

Let us assume μ be the refractive index of the unknown material

according to snell's law of refraction.

μ₁ sin i = μ₂ sin r

1.21 × sin 41.9° = μ × sin 37.3°

μ = 1.33

hence the refractive index of the unknown material comes out top be 1.33

6 0

3 years ago