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vovangra [49]
3 years ago
6

Help plzDoes everyone in the earth experience solar eclipse?​

Physics
2 answers:
kaheart [24]3 years ago
4 0

Answer:

while all of the world can experience a solar eclipse it is not normally at the same time so one part of the earth might have it but not the other and even in one area if there is one in north america like the last one in texas we did not have a full eclipse

neonofarm [45]3 years ago
4 0

Answer: To answer your question.Not at all because the shadow that the moon cast on the earth is not very broad,as the earth rotates ,the path of the total eclipse is a narrow one.

Total solar eclipses are rare events actually. Although they occur somewhere on Earth every 18 months on average, this is estimated to recur at any given place only once every 360 to 410 years, on average as the case may be .

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Answer:

    K = m g (A - A2)

Explanation:

In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential

         Em = U₀ = m g A

For when the system is at an ele

Elongation A2 less than A, energy has two parts

        Em = K + U₂

       K = Em –U₂

We substitute

     K = m g A - m gA2

    K = m g (A - A2)

3 0
3 years ago
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Based on the law of conservation of energy, which statement is false?
alexgriva [62]

I think it’s Energy is lost when machines don’t work right.

8 0
3 years ago
A 1,680 kg satellite is in a circular orbit around Earth with a tangential speed of 6,578 m/s. What is the height of the satelli
balu736 [363]

Answer:

Recall that Earth’s radius is 6.38 × 106 m and Earth’s mass is 5.97 × 1024 kg.

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Joe and Max shake hands and say goodbye. Joe walks east 0.40 km to a coffee shop, and Max flags a cab and rides north 3.65 km to
katen-ka-za [31]

Answer:

3.67 km

Explanation:

Joe distance towards coffee shop is,

OB=0.40 km

And the Max distance towards bookstore is,

OA=3.65 km

Now the distance between the Joy and Max will be,

By applying pythagorus theorem,

AB=\sqrt{OB^{2}+OA^{2}}

Substitute 0.40 km for OB and 3.65 km for OA in the above equation.

AB=\sqrt{0.40^{2}+3.65^{2}}\\AB=\sqrt{13.4825} \\AB=3.67 km

Therefore the distance between there destination is 3.67 km.

6 0
3 years ago
3. A cat pushes a 0.25-kg toy with a net force of 8 N. According to Newton's second
jek_recluse [69]
  • Mass=0.25kg
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\\ \sf{:}\!\implies F=ma

\\ \sf{:}\!\implies Acceleration=\dfrac{F}{m}

\\ \sf{:}\!\implies Acceleration=\dfrac{8}{0.25}

\\ \sf{:}\!\implies Acceleration=32m/s^2

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