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2 years ago

A bus travelling 30.0 km/h east has a constant increase in speed of 1.5 m/s. What is its velocity 6.8s later

Physics

1 answer:

alekssr [168]2 years ago

7 0

Answer:

8.72 seconds before

Explanation:

and 27.1 secs after

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Which events may occur when ocean salinity increases? Check all that apply.

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The answer is number two, number four, and number one

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2 years ago

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If you wanted to increase the gravitational force between two objects what would you do

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Double the force on the object

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3 years ago

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Problem 1 Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed

ANTONII [103]

Answer:

markers are 29.76 m far apart in the laboratory

Explanation:

Given the data in the question;

speed of particle = 0.624c

lifetime = 159 ns = 1.59 × 10⁻⁷ s

we know that; c is speed of light which is equal to 3 × 10⁸ m/s

we know that

distance = vt

or s = ut

so we substitute

distance = 0.624c × 1.59 × 10⁻⁷ s

distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s

distance = 1.872 × 10⁸ m/s × 1.59 × 10⁻⁷ s

distance = 29.76 m

Therefore, markers are 29.76 m far apart in the laboratory

3 0

2 years ago

13. A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V a

Lisa [10]

Answer:

The output power is 2 kW

Explanation:

It is given that,

Number of turns in primary coil, $N_p=250$

Number of turns in secondary coil, $N_s=500$

Voltage of primary coil, $V_p=200\ V$

Current drawn from secondary coil, $I_s=5\ A$

We need to find the power output. It is equal to the product of voltage and current. Firstly, we will find the voltage of secondary coil as :

$\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}$

$\dfrac{250}{500}=\dfrac{200}{V_s}$

$V_s=400\ V$

So, the power output is :

$P_s=V_s\times I_s$

$P_s=400\ V\times 5\ A$

$P_s=2000\ watts$

$P_s=2\ kW$

So, the output power is 2 kW. Hence, this is the required solution.

8 0

2 years ago

A 23.0 kg block at rest on a horizontal frictionless air track is connected to the wall via a spring. The equilibrium position o

lara [203]

Answer:

Explanation:

We use the harmonic motion position equation:

$x(t) = A\cos(\omega t+\phi)$

where A = 0.350 and for t = 0

$x(0) A = A\ cos(\phi)$

so: $\phi = 0$

and also:

$\omega = \frac{2\pi}{T} = \frac{2\pi}{4.10} = 1.532 rad/s$

so we have:

x(t)=0.350cos(1.532 t)

For t = 3.403 s

x(3.403)=0.350cos(1.532 (3.403)) = 0.348 m

3 0

3 years ago