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3 years ago

Find the equation of the cosine graphed.

Mathematics

1 answer:

Lunna [17]3 years ago

7 0

Answer:

C) y = -cos(x) +2

Step-by-step explanation:

The centerline is 2, so 2 is added. That leaves out choices A and B.

There is a minimum (not a maximum) at x=0, so the multiplier is negative, eliminating choice D.

The correct equation is that of C: y = -cos(x) +2.

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Is 0.9 <,>,or = to 4/25

Nina [5.8K]

Answer:

greater than (>)

Step-by-step explanation:

4/25=0.16

0.9>0.16

8 0

3 years ago

Geometry

Genrish500 [490]

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.

Bingel [31]

Answer:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

Step-by-step explanation:

For this case we want to find the following integral:

$\int_{-\infty}^{-5} x^{-2}dx$

And we can solve the integral on this way:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}$

$\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}$

And if we evaluate the integral using the fundamental theorem of calculus we got:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

8 0

3 years ago

An object is acted upon by the forces F1=<10,6,4> and F2=<0,3,9>. Find the force F3 that must act on the object

murzikaleks [220]

$\vec F_3=\langle x,y,z\rangle$ is a force vector such that

$\vec F_1+\vec F_2+\vec F_3=\vec0$

$\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle$

$\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13$

So the missing force is

$\boxed{\vec F_3=\langle-10,-9,-13\rangle}$

8 0

3 years ago

Find the possible values for s in the inequality 12s – 20 ≤ 50 – 3s – 25.

Margaret [11]

◆ INEQUALITIES ◆

$given \: expression \: \: - \\ \\ 12s - 20 \leqslant 50 - 3s - 25 \\ \\ 12s - 20 \leqslant 25 - 3s \\ \\ adding \: 20 \: both \: sides \: \: , \: \\ we \: get \: - \\ \\ 12 s \leqslant 45 - 3s \\ \\ 12s + 3s \leqslant 45 \\ \\ 15s \leqslant 45 \\ s \leqslant \frac{45}{15} \\ \\ \\ s \leqslant 3 \: \: \: \: \: \: ans.$

8 0

3 years ago