Graph the following function on the axes provided.

Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re

kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read $13\frac{3}{4}$ pages in $\frac{1}{4}$ of an hour.

Therefore, pages read by Zander in 1 hour = $\frac{\text{Total pages read}}{\text{Total time taken}}$

= $\frac{13\frac{3}{4}}{\frac{1}{4}}$

= $\frac{55}{4}\times \frac{4}{1}$

= 55 pages per hour

Sydney read $43\frac{1}{3}$ pages in $\frac{2}{3}$ of an hours.

Pages read by Sydney in 1 hour = $\frac{43\frac{1}{3}}{\frac{2}{3} }$

= $\frac{130}{3}\times \frac{3}{2}$

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

4 0

2 years ago

What is the slope intercept and point slope form

noname [10]

Slope intercept is y=Mx+b where m is always the slope and b is always your y intercept. The point slope fo is y-y^1=m(x-x^1) where x1 and y1 are a known point and m is the still the slope. X and y is another point on the linear equation

3 0

2 years ago

The dimensions of a box that is a rectangular prism are 3 inches, 4 inches, and 6 inches. What is the length of the diagonal fro

Neporo4naja [7]

Answer:

7.8 in

Step-by-step explanation:

Given:-

- The dimension of rectangular prism:

(3 x 4 x 6) inches

Find:-

What is the length of the diagonal from the point R to point S, to the nearest tenth of an inch?

Solution:-

- We will set up an origin with coordinates ( 0 , 0 , 0 ) at point R. Then the coordinates of point S would be ( 3 , 4 , 6 ).

- Then we will use the distance between two points formula in cartesian coordinate system:

Distance = $\sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}$

Where the coordinates of two points ( x1 , y1 , z1 ) & ( x2 , y2 , z2 ).

- Using R( 0 , 0 , 0 ) & S( 3 , 4 , 6 ), the distance |RS| would be:

$|RS| = \sqrt{(0 - 3)^2 + (0 - 4)^2 + (0 - 6)^2}\\\\|RS| = \sqrt{ 9 + 16 + 36}\\\\|RS| = \sqrt{61} = 7.81024$

- The distance |RS| to nearest 10th of an inch is = 7.8 in

4 0

2 years ago

Given sec(theta)= 5... find cot(90-theta)

Mumz [18]

$\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 } = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} 
\\
\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6} 
\\
$

3 0

2 years ago

The tape diagram below represents 100\%100%100, percent.

elena-s [515]

Answer:

75 %

Step-by-step explanation:

100/4=25

25x3=75

6 0

2 years ago