Neither energy nor matter can enter and exit an isolated system.
Explanation:
There are three types of systems which refers to universe. They are
1. Open System : In an open system, both energy and matter have external interactions. Example:- boiling water in an open pan.
2. Closed system : In a closed system, only energy has interaction with surroundings. Example:- boiling water with a lid on the pan.
3. Isolated system : In an isolated system, neither energy-nor matter has external interactions with surroundings. Example : a thermos flask does not exchange energy and matter.
Hence, the correct option is (a) " neither energy nor matter ".
FORCE ACTING ON THE BODY , F = 200N
AREA ON WHICH THE FORCE IS ACTING , A = 0.05 CM²
= 0.05*(10⁻²)
= 0.05*10⁻² M²
TO CONVERT CM TO M * BY 10⁻²
PRESSURE = FORCE / AREA
PRESSURE = 200/0.05*10⁻⁴
= 200*10⁴/0.05
= 200*10⁴*10²/5
= 20*10⁵/5
= 4*10⁵ N/M².
HOPE THIS HELPS.
Wassily Kandinsky invented abstract geometry :) have a good week
Answer:
φ = B sin (2π n/a x)
Explanation:
In quantum mechanics when a particle moves freely it implies that the potential is zero (V = 0), so its wave function is
φ = A cos kx + B sin kx
we must place the boundary conditions to determine the value of the constants A and B.
In our case we are told that the particle cannot be outside the boundary given by x = ± a / 2
therefore we must make the cosine part zero, for this the constant A = 0, the wave function remains
φ = B sin kx
the wave vector is
k = 2π /λ
now let's adjust the period, in the border fi = 0 therefore the sine function must be zero
φ (a /2) = 0
0 = A sin (2π/λ a/2)
therefore the sine argument is
2π /λ a/2 = n π
λ= a / n
we substitute
φ = B sin (2π n/a x)