Which equation describes the fastest runner?

Physics

2 answers:

fomenos3 years ago

8 0

The equation distance $\bold{=2 \times \text { time }}$ describes the fastest runner.

Answer: Option D

<u>Explanation: </u>

The fastest runner is determined by how quick a person can reach the destination (i.e) in a less amount of time compared to others. Consider it took 10 seconds to the reach the destination x. Substitute time = 10 seconds,

$0.5 \times 10=5$

$0.33 \times 10=3.3$

$0 \times 10=0$

$2 \times 10=20$

From the four options, the highest distance travelled for constant time is distance $\bold{=2 \times \text {time}}$ .

irina [24]3 years ago

7 0

I think the answer will be A

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$x_{1}=x_{o}+v_{ox}t_{1}=67.0m\\0+4.50v_{o}Cos\alpha =67.0m\\v_{o}Cos\alpha =14.99\\v_{o}=14.99/Cos\alpha.....(1) \\and\\y_{1}=y_{o}+v_{oy}t_{1}+(1/2)a_{oy}t_{1}^{2} =0m\\ 1+4.50v_{o}Sin\alpha+(-9.8/2)(4.5)^{2}=0\\ v_{o}Sin\alpha=21.828.....(2)$

Put the value of v₀ from equation (1) to equation (2)

$\frac{14.99}{Cos\alpha }(Sin\alpha ) =21.828\\as\\tan\alpha =Sin\alpha /Cos\alpha \\So\\14.99tan\alpha =21.828\\tan\alpha =21.828/14.99\\\alpha =tan^{-1}(21.828/14.99) \\\alpha =55.52^{o}$