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2 years ago

Which equation describes the fastest runner?

Physics

2 answers:

fomenos2 years ago

8 0

The equation distance $\bold{=2 \times \text { time }}$ describes the fastest runner.

Answer: Option D

Explanation:

The fastest runner is determined by how quick a person can reach the destination (i.e) in a less amount of time compared to others. Consider it took 10 seconds to the reach the destination x. Substitute time = 10 seconds,

$0.5 \times 10=5$

$0.33 \times 10=3.3$

$0 \times 10=0$

$2 \times 10=20$

From the four options, the highest distance travelled for constant time is distance $\bold{=2 \times \text {time}}$ .

irina [24]2 years ago

7 0

I think the answer will be A

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Balancing equations

kolbaska11 [484]

Answer:

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Explanation:

I dont know what the question is

3 0

2 years ago

Can someone help me a bit on this? Will mark brainliest. ( no physical science option soooo)

Advocard [28]

Answer:

When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts (how much it fans out) depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.

The corresponding relation for diffraction is

$d sin(\theta) \approx \lambda$ ,

where $\lambda$ is the wavelength of light, $d$ is the slit width, and $\theta$ is the diffraction angle.

From this relation we clearly see that the diffraction angle $\theta$ is directly proportional to the wavelength $\lambda$ of light—longer the wavelength larger the diffraction angle.

7 0

3 years ago

The human ear canal is about 2.9 cm long and can be regarded as a tube open at one end and closed at the eardrum. What is the fu

solniwko [45]

The frequency of the human ear canal is 2.92 kHz.

Explanation:

As the ear canal is like a tube with open at one end, the wavelength of sound passing through this tube will propagate 4 times its length of the tube. So wavelength of the sound wave will be equal to four times the length of the tube. Then the frequency can be easily determined by finding the ratio of velocity of sound to wavelength. As the velocity of sound is given as 339 m/s, then the wavelength of the sound wave propagating through the ear canal is

Wavelength=4*Length of the ear canal

As length of the ear canal is given as 2.9 cm, it should be converted into meter as follows:

$wavelength = 4*2.9*10^{-2} =0.116$

Then the frequency is determined as

f=c/λ=339/0.116=2922 Hz=2.92 kHz.

So, the frequency of the human ear canal is 2.92 kHz.

4 0

3 years ago

The three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to air resistance and the u

irinina [24]

Explanation :

The forces acting on hot- air balloon are:

Weight, (W)

Force due to air resistance, (F)

Upthrust force, (U)

Its weight W is acting in downward direction. The upthrust force U acts in upward direction. When the balloon is moving upward, the air resistance is in downward and vice versa.

In this case, the hot-air balloon descends vertically at constant speed.

so, $a=0$