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miss Akunina [59]
3 years ago
9

Which element has an atomic number of 9 and an atomic mass of 19?

Physics
2 answers:
MA_775_DIABLO [31]3 years ago
6 0
I honestly don’t know but i have to answer something just kidding it’s c
yan [13]3 years ago
3 0

Answer:

fluorine

Explanation:

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An airplane was 300 km [N] of Toronto airport, 3 hours later the airplane 600 km [S]
Alecsey [184]

Answer:

Explanation:

a) 300 + 600 = 900 km S

b) 900/3 = 300 km/hr S

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cluponka [151]

<span><span>Department of Highway Safety and Motor Vehicles          OR</span></span>

<span><span /><span><span>Division of Highway Safety and Motor Vehicles </span></span></span>

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3 years ago
What is the function of a hypothesis in the scientific inquiry process
iris [78.8K]
You can use them by analyzing the way you can solve it.
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3 years ago
Calculate how much work is required to launch a spacecraft of mass m from the surface of the earth (mass mE, radius RE) and plac
mylen [45]

To solve this problem it is necessary to apply the concepts related to the conservation of energy, through the balance between the work done and its respective transformation from the gravitational potential energy.

Mathematically the conservation of these two energies can be given through

W = U_f - U_i

Where,

W = Work

U_f = Final gravitational Potential energy

U_i = Initial gravitational Potential energy

When the spacecraft of mass m is on the surface of the earth then the energy possessed by it

U_i = \frac{-GMm}{R}

Where

M = mass of earth

m = Mass of spacecraft

R = Radius of earth

Let the spacecraft is now in an orbit whose attitude is R_{orbit} \approx R then the energy possessed by the spacecraft is

U_f = \frac{-GMm}{2R}

Work needed to put it in orbit is the difference between the above two

W = U_f - U_i

W = -GMm (\frac{1}{2R}-\frac{1}{R})

Therefore the work required to launch a spacecraft from the surface of the Eart andplace it ina circularlow earth orbit is

W = \frac{GMm}{2R}

3 0
3 years ago
12) Does the label “centripetal force” ever appear in an FBD?
Murrr4er [49]
"Though a force, or a resulting sum of forces, may be centripetal, there is not an actual "Centripetal Force" that would appear on an FBD. Since an FBD is a diagram of physical forces at work upon a body, and a centripetal force is not the reaction of some physical object upon another, it would not be proper to show it. You might have a tension force, a weight force, a normal force, electric forces, magnetic forces, or any number of reactions, but actually labeling any of them "centripetal" would be unconventional".
-Yahoo
6 0
3 years ago
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