Answer: Some species of mosquitoes lay their eggs on water or on vegetation very near to water because their larval instars are aquatic. Thus, when the eggs hatch the first instar larvae will already be in the larval media. Some species of Aedes mosquitoes lay their drought resistant eggs on the soil of dried up playa lake beds. When it rains, the moisture will serve as a hatching stimulus and the eggs will hatch and spend their larval instars in the pools of rainfall. Other mosquito female will lay their eggs in the water of plant axils, tree holes and related plant habitats. In each of these instances, the immature mosquito instars require water in larval development and molt into adult insects.
hope it helps you
Converting a decimal number into binary would be:
192/2= 96 remainder=0
96/2= 48 remainder=0
48/2=24 remainder=0
24/2=12 remainder=0
12/2=6 remainder=0
6/2=3 remainder=0
3/2=1 remainder=1
1/2= 0 remainder=1
The binary number would be: 11 00 00 00
For 16
16/2=8 remainder=0
8/2=4 remainder=0
4/2=2 remainder=0
2/2=1 remainder=0
1/2= 0 remainder=1
The binary would be: 00 01 00 00
For 3
3/2=1 remainder=1
1/2= 0 remainder=1
The binary would be: 00 00 00 11
For 1
1/2= 0 remainder=1
The binary would be: 00 00 00 01
The binary number would be:
11000000.00010000.00000011.00000001
Answer:
1. Access and share internal information quickly and safely
Explanation:
<u>Answer:</u>
<em>void main ( ) </em>
<em> { </em>
<em> int counter; </em>
<em> cout<<""Even numbers between 1 to 20 are:""<<endl ; </em>
<em> //Method 1
</em>
<em> for (counter = 1; counter <= 20; counter++) </em>
<em> { </em>
<em> if ( counter%2 == 0) </em>
<em> {
</em>
<em> cout<<counter<<""\t""<<endl ; </em>
<em> } </em>
<em> } </em>
<em>//Method 2 – simplest one
</em>
<em>for (counter = 2; counter <= 20;) </em>
<em> { </em>
<em> cout<<counter<<""\t""<<endl ; </em>
<em>counter = counter + 2;
</em>
<em> </em>
<em> }
</em>
<em>
</em>
<em> return 0; </em>
<em>}
</em>
<u>Explanation:</u>
In this, Method 1 runs a for loop and check whether each number is divided by 2. If yes, then printed otherwise it is skipped.
In the second method, it runs for loop only for even numbers. <em>This is obtained by incrementing the counter by 2.
</em>
I’d say monthly. It probably wouldn’t kill you to do it every three months though.